![SearchIcon](https://vmkt.vedantu.com/vmkt/PROD/png/bdcdbbd8-08a7-4688-98e6-4aa54e5e0800-1733305962725-4102606384256179.png)
Explain Friedel-Craft alkylation of chlorobenzene. Give an equation.
Answer
411.6k+ views
Hint : An alkyl group can be added to a benzene molecule by an electrophilic aromatic substitution reaction called the Friedel‐Crafts alkylation reaction. One example is the addition of a methyl group to a benzene ring. The mechanism for this reaction begins with the generation of a methyl carbocation from methyl bromide.
Complete Step By Step Answer:
Friedel-Crafts Alkylation refers to the replacement of an aromatic proton with an alkyl group. This is done through an electrophilic attack on the aromatic ring with the help of a carbocation. The Friedel-Crafts alkylation reaction is a method of generating alkyl benzenes by using alkyl halides as reactants.
A Lewis acid catalyst such as $ FeC{l_3} $ or $ AlC{l_3} $ is employed in this reaction in order to form a carbocation by facilitating the removal of the halide. The resulting carbocation undergoes a rearrangement before proceeding with the alkylation reaction.
Additional Information:
Mechanism:
The Friedel-Crafts alkylation reaction proceeds via a three-step mechanism.
Step 1
The Lewis acid catalyst ( $ AlC{l_3} $ ) undergoes a reaction with the alkyl halide, resulting in the formation of an electrophilic carbocation.
Step 2
The carbocation proceeds to attack the aromatic ring, forming a cyclohexadienyl cation as an intermediate. The aromaticity of the arene is temporarily lost due to the breakage of the carbon-carbon double bond.
Step 3
The deprotonation of the intermediate leads to the reformation of the carbon-carbon double bond, restoring aromaticity to the compound. This proton goes on to form hydrochloric acid, regenerating the $ AlC{l_3} $ catalyst.
Note :
Friedel craft alkylation will undergo that aromatic compound, which is electron-rich. As it is the electrophilic substitution reaction. But, since the carbo-cations formed by aryl and vinyl halides are extremely unstable, they cannot be used in this reaction. And also the presence of a deactivating group on the aromatic ring can lead to the deactivation of the catalyst due to the formation of complexes.
Complete Step By Step Answer:
Friedel-Crafts Alkylation refers to the replacement of an aromatic proton with an alkyl group. This is done through an electrophilic attack on the aromatic ring with the help of a carbocation. The Friedel-Crafts alkylation reaction is a method of generating alkyl benzenes by using alkyl halides as reactants.
![seo images](https://www.vedantu.com/question-sets/3498fbcf-d2f7-451c-9250-3b3b59d09a458732527859306975433.png)
A Lewis acid catalyst such as $ FeC{l_3} $ or $ AlC{l_3} $ is employed in this reaction in order to form a carbocation by facilitating the removal of the halide. The resulting carbocation undergoes a rearrangement before proceeding with the alkylation reaction.
Additional Information:
Mechanism:
The Friedel-Crafts alkylation reaction proceeds via a three-step mechanism.
Step 1
The Lewis acid catalyst ( $ AlC{l_3} $ ) undergoes a reaction with the alkyl halide, resulting in the formation of an electrophilic carbocation.
Step 2
The carbocation proceeds to attack the aromatic ring, forming a cyclohexadienyl cation as an intermediate. The aromaticity of the arene is temporarily lost due to the breakage of the carbon-carbon double bond.
Step 3
The deprotonation of the intermediate leads to the reformation of the carbon-carbon double bond, restoring aromaticity to the compound. This proton goes on to form hydrochloric acid, regenerating the $ AlC{l_3} $ catalyst.
Note :
Friedel craft alkylation will undergo that aromatic compound, which is electron-rich. As it is the electrophilic substitution reaction. But, since the carbo-cations formed by aryl and vinyl halides are extremely unstable, they cannot be used in this reaction. And also the presence of a deactivating group on the aromatic ring can lead to the deactivation of the catalyst due to the formation of complexes.
Recently Updated Pages
Master Class 11 Accountancy: Engaging Questions & Answers for Success
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Glucose when reduced with HI and red Phosphorus gives class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The highest possible oxidation states of Uranium and class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Find the value of x if the mode of the following data class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which of the following can be used in the Friedel Crafts class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
A sphere of mass 40 kg is attracted by a second sphere class 11 physics CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
10 examples of friction in our daily life
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Prokaryotic Cells and Eukaryotic Cells
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
State and prove Bernoullis theorem class 11 physics CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What organs are located on the left side of your body class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Define least count of vernier callipers How do you class 11 physics CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The combining capacity of an element is known as i class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)