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Explain hybridization of central atoms in CCl4.

Answer
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Hint: There are mainly three types of orbital hybridization in chemistry: sp3, sp2, and sp. The state of hybridization of an atom can be determined from the steric number of that atom. The steric number is calculated from the Lewis structure of the respective molecule.

Complete answer:
Carbon tetrachloride is a liquid organic compound that has a molecular formula CCl4. It is widely used as a solvent in various organic chemical reactions. The central atom of this molecule is obviously carbon (C) and four chlorine atoms are attached to it by four σ-bonds.
The state of hybridization of an atom in a particular molecule can be obtained by determining the steric number (SN) of that atom.
The steric number is the summation of the number of lone pairs of electrons present on the atom and the number of atoms that are directly attached to that. Mathematically, it can be represented as:
SN = (lone pairs of electrons on the atom) + (number of atoms directly bonded to the atom)
Now, the steric number is related to the state of hybridization is as follows:
If the steric number is 2, then the hybridization is sp.
If the steric number is 3, then the hybridization is sp2.
If the steric number is 4, then the hybridization is sp3.
Now, the steric number can be evaluated from the Lewis structure of a molecule.
The Lewis structure of CCl4is given below:
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From the above structure, it can be concluded that,
Lone pairs on carbon atom is 0
Number of atoms that are bonded to carbon atom is 4
Hence, the steric number will be:
SN = (0+4) = 4
Since, the steric number of carbon atoms is found to be four, then we can say that the state of hybridization of carbon atoms is sp3.
Hence, the hybridization of the central atom in CCl4 is sp3.

Note: The shape and geometry of a molecule depends upon the hybridization state of the central atom of a molecule. If the central atom is Sp3 hybridized, then both the geometry and the shape of the molecule will be tetrahedral.
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