
Explain positive, negative and zero work. Give one example of each.
Answer
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Hint: Write formula of work $W=\overrightarrow{F}\cdot \overrightarrow{r}$. Learn dot product of two forces. For positive work, W should be positive so for this find an angle between force and displacement.
Dot product of two component A and B
$\overrightarrow{A}\cdot \overrightarrow{B}=AB\cos \theta $
Where $\theta $ is the angle between two vectors.
$\overrightarrow{F}\cdot \overrightarrow{r}=Fr\cos \theta $
Find $\theta $ for positive W, negative W and zero W.
Complete step by step answer:
The work done by a force on a particle during a displacement is given as
$W=\overrightarrow{F}\cdot \overrightarrow{r}$
Here, W = work
$\overrightarrow{F}$= force
$\overrightarrow{r}$= displacement
Positive work done – The work done is said to be positive when force and displacement are in the same direction.
$\begin{align}
& \theta ={{0}^{{}^\circ }} \\
& \overrightarrow{F}\cdot \overrightarrow{r}=Fr\cos \theta \\
& \overrightarrow{F}\cdot \overrightarrow{r}=Fr\cos {{0}^{{}^\circ }} \\
& \overrightarrow{F}\cdot \overrightarrow{r}=Fr \\
& W=\overrightarrow{F}\cdot \overrightarrow{r}=Fr \\
\end{align}$
Hence, work is positive.
Zero work – the work done is said to be zero when force and displacement are perpendicular to each other.
$\begin{align}
& \theta ={{90}^{{}^\circ }} \\
& \overrightarrow{F}\cdot \overrightarrow{r}=Fr\cos \theta \\
& \overrightarrow{F}\cdot \overrightarrow{r}=Fr\cos {{90}^{{}^\circ }} \\
& \overrightarrow{F}\cdot \overrightarrow{r}=0 \\
& W=\overrightarrow{F}\cdot \overrightarrow{r}=0 \\
\end{align}$
Hence, work is zero
Negative work done – The work done is said to be negative when force and displacement are in opposite directions.
$\begin{align}
& \theta ={{180}^{{}^\circ }} \\
& \overrightarrow{F}\cdot \overrightarrow{r}=Fr\cos \theta \\
& \overrightarrow{F}\cdot \overrightarrow{r}=Fr\cos {{180}^{{}^\circ }} \\
& \overrightarrow{F}\cdot \overrightarrow{r}=-Fr \\
& W=\overrightarrow{F}\cdot \overrightarrow{r}=-Fr \\
\end{align}$
Hence, work is negative.
Note: Work done by friction is always zero because friction force and displacement act in opposite directions. When a spring travels from A to B and from B back to A then work done during the return journey is negative of the work during the onwards journey and the net work done by the spring is zero.
Dot product of two component A and B
$\overrightarrow{A}\cdot \overrightarrow{B}=AB\cos \theta $
Where $\theta $ is the angle between two vectors.
$\overrightarrow{F}\cdot \overrightarrow{r}=Fr\cos \theta $
Find $\theta $ for positive W, negative W and zero W.
Complete step by step answer:
The work done by a force on a particle during a displacement is given as
$W=\overrightarrow{F}\cdot \overrightarrow{r}$
Here, W = work
$\overrightarrow{F}$= force
$\overrightarrow{r}$= displacement
Positive work done – The work done is said to be positive when force and displacement are in the same direction.
$\begin{align}
& \theta ={{0}^{{}^\circ }} \\
& \overrightarrow{F}\cdot \overrightarrow{r}=Fr\cos \theta \\
& \overrightarrow{F}\cdot \overrightarrow{r}=Fr\cos {{0}^{{}^\circ }} \\
& \overrightarrow{F}\cdot \overrightarrow{r}=Fr \\
& W=\overrightarrow{F}\cdot \overrightarrow{r}=Fr \\
\end{align}$

Hence, work is positive.
Zero work – the work done is said to be zero when force and displacement are perpendicular to each other.
$\begin{align}
& \theta ={{90}^{{}^\circ }} \\
& \overrightarrow{F}\cdot \overrightarrow{r}=Fr\cos \theta \\
& \overrightarrow{F}\cdot \overrightarrow{r}=Fr\cos {{90}^{{}^\circ }} \\
& \overrightarrow{F}\cdot \overrightarrow{r}=0 \\
& W=\overrightarrow{F}\cdot \overrightarrow{r}=0 \\
\end{align}$
Hence, work is zero

Negative work done – The work done is said to be negative when force and displacement are in opposite directions.

$\begin{align}
& \theta ={{180}^{{}^\circ }} \\
& \overrightarrow{F}\cdot \overrightarrow{r}=Fr\cos \theta \\
& \overrightarrow{F}\cdot \overrightarrow{r}=Fr\cos {{180}^{{}^\circ }} \\
& \overrightarrow{F}\cdot \overrightarrow{r}=-Fr \\
& W=\overrightarrow{F}\cdot \overrightarrow{r}=-Fr \\
\end{align}$
Hence, work is negative.
Note: Work done by friction is always zero because friction force and displacement act in opposite directions. When a spring travels from A to B and from B back to A then work done during the return journey is negative of the work during the onwards journey and the net work done by the spring is zero.
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