Answer
Verified
488.1k+ views
Hint: In this question use the concept that potentiometer helps establish the relationship between the potential drop (say emf) and the length across which the potential drop is to be measured. This will help understand the principle on which potentiometer works.
Complete Step-by-Step solution:
Principle of potentiometer:
The principle of potentiometer is that, for a wire having uniform area of cross section, the potential drop in the wire is directly proportional to its length.
The above principle is valid only when the potentiometer is used in comparing the EMF of two cells.
For example:
Consider two potentiometers the length of the first potentiometer is 10 cm and another potentiometer is 20 cm if the EMF of the first potentiometer is 5 V then what is the EMF of another potentiometer.
So according to above information we have,
$ \Rightarrow EMF \propto {\text{length}}$
$ \Rightarrow \dfrac{{{{\left( {EMF} \right)}_1}}}{{{{\left( {EMF} \right)}_2}}} = \dfrac{{{L_1}}}{{{L_2}}}$
$ \Rightarrow \dfrac{5}{{{{\left( {EMF} \right)}_2}}} = \dfrac{{10}}{{20}}$
$ \Rightarrow {\left( {EMF} \right)_2} = 10$ V.
So the EMF of another cell is 10 V.
So this is the required answer.
Note – There is always a great bit of confusion between a potentiometer and a rheostat. A potentiometer is a three terminal device used for current control and a rheostat is an electromechanical device designed so that the resistance values can easily be changed. A rheostat is used in potentiometer assembly so as to vary the resistance across specific lengths of potentiometer.
Complete Step-by-Step solution:
Principle of potentiometer:
The principle of potentiometer is that, for a wire having uniform area of cross section, the potential drop in the wire is directly proportional to its length.
The above principle is valid only when the potentiometer is used in comparing the EMF of two cells.
For example:
Consider two potentiometers the length of the first potentiometer is 10 cm and another potentiometer is 20 cm if the EMF of the first potentiometer is 5 V then what is the EMF of another potentiometer.
So according to above information we have,
$ \Rightarrow EMF \propto {\text{length}}$
$ \Rightarrow \dfrac{{{{\left( {EMF} \right)}_1}}}{{{{\left( {EMF} \right)}_2}}} = \dfrac{{{L_1}}}{{{L_2}}}$
$ \Rightarrow \dfrac{5}{{{{\left( {EMF} \right)}_2}}} = \dfrac{{10}}{{20}}$
$ \Rightarrow {\left( {EMF} \right)_2} = 10$ V.
So the EMF of another cell is 10 V.
So this is the required answer.
Note – There is always a great bit of confusion between a potentiometer and a rheostat. A potentiometer is a three terminal device used for current control and a rheostat is an electromechanical device designed so that the resistance values can easily be changed. A rheostat is used in potentiometer assembly so as to vary the resistance across specific lengths of potentiometer.
Recently Updated Pages
Arrange the following elements in the order of their class 10 chemistry CBSE
In the following figure the value of resistor to be class 10 physics CBSE
What is the maximum resistance which can be made using class 10 physics CBSE
The magnetic induction at point P which is at a distance class 10 physics CBSE
According to Mendeleevs Periodic Law the elements were class 10 chemistry CBSE
Fill in the blanks with suitable prepositions Break class 10 english CBSE
Trending doubts
When was Karauli Praja Mandal established 11934 21936 class 10 social science CBSE
The term ISWM refers to A Integrated Solid Waste Machine class 10 social science CBSE
Name five important trees found in the tropical evergreen class 10 social studies CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Change the following sentences into negative and interrogative class 10 english CBSE
Why is there a time difference of about 5 hours between class 10 social science CBSE