Answer
Verified
502.8k+ views
Hint: Divide and multiply a number so that the complex number can be expressed in terms of sine & cosine of angles.
Lets say, $x = 1 + i\sqrt 3$
Multiply and divide the RHS of the above equation with $2$.
$
x = 2\left( {\dfrac{{1 + i\sqrt 3 }}{2}} \right) = 2\left( {\dfrac{1}{2}} \right) + 2\left( {\dfrac{{i\sqrt 3 }}{2}} \right) \\
x = 2\cos \dfrac{\pi }{3} + i2\sin \left[ {\dfrac{\pi }{3}} \right] \\
$
This above equation can be written in exponential form
As we know $\cos \theta + i\sin \theta = {e^{i\theta }}$
Doing the same in the equation obtained we get,
$x = 2{e^{i\dfrac{\pi }{3}}}$
Hence, $2{e^{i\dfrac{\pi }{3}}}$ in modulus amplitude form.
Note :- In these types of questions we have to obtain the given equation in the form of $\cos \theta + i\sin \theta = {e^{i\theta }}$ to convert it into modulus amplitude form. We should also be aware of trigonometric values needed to convert the equation in general form.
Lets say, $x = 1 + i\sqrt 3$
Multiply and divide the RHS of the above equation with $2$.
$
x = 2\left( {\dfrac{{1 + i\sqrt 3 }}{2}} \right) = 2\left( {\dfrac{1}{2}} \right) + 2\left( {\dfrac{{i\sqrt 3 }}{2}} \right) \\
x = 2\cos \dfrac{\pi }{3} + i2\sin \left[ {\dfrac{\pi }{3}} \right] \\
$
This above equation can be written in exponential form
As we know $\cos \theta + i\sin \theta = {e^{i\theta }}$
Doing the same in the equation obtained we get,
$x = 2{e^{i\dfrac{\pi }{3}}}$
Hence, $2{e^{i\dfrac{\pi }{3}}}$ in modulus amplitude form.
Note :- In these types of questions we have to obtain the given equation in the form of $\cos \theta + i\sin \theta = {e^{i\theta }}$ to convert it into modulus amplitude form. We should also be aware of trigonometric values needed to convert the equation in general form.
Recently Updated Pages
The oxidation process involves class 11 chemistry JEE_Main
For the redox reaction MnO4 + C2O42 + H + to Mn2 + class 11 chemistry JEE_Main
During the electrolysis of sodium ethanoate the gas class 11 maths JEE_Main
1bromo3chlorocyclobutane when treated with two equivalents class 11 chem sec 1 JEE_Main
The transalkenes are formed by the reduction of alkynes class 11 chemistry JEE_Main
A uniform rod of length L and mass M is pivoted at class 11 physics JEE_Main
Trending doubts
Which is the longest day and shortest night in the class 11 sst CBSE
Why is steel more elastic than rubber class 11 physics CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Define the term system surroundings open system closed class 11 chemistry CBSE
In a democracy the final decisionmaking power rests class 11 social science CBSE
In the tincture of iodine which is solute and solv class 11 chemistry CBSE