Answer
Verified
440.4k+ views
Hint: In order to mention the formula of ferric sulphate we are required to know the structure. Recall that the word ‘ferric’ indicates that the oxidation state of the $Fe$ atom is +3.
Complete step by step answer:
First, we should look at the oxidation states of ions involved in the making of this molecule. The word ferric indicates that the oxidation state of the $Fe$ ion is +3 and the word sulphate indicates that the formula of the ion present is $S{{O}_{4}}$ we know that this ion has an oxidation state of -2 so we can rule out ‘option B’ since it has the $S{{O}_{3}}$ ion. We know that the overall charge on the molecule is 0, so we can balance the charges to find the number of each ion involved in the molecule.
We see by trial and error method by considering all the options given that only in option ‘D. \[F{{e}_{2}}{{\left( S{{O}_{4}} \right)}_{3}}\]’ the overall charge comes out to be 0 (It is +1 in option A and -1 in option C).
The structure of Ferric sulphate is given below:
Hence, the answer is. \[F{{e}_{2}}{{\left( S{{O}_{4}} \right)}_{3}}\]’.
So, the correct answer is “Option B”.
Note: Remember that when the ion $S{{O}_{3}}^{2-}$ is involved, the word sulphite will be used in the naming of the molecule. The word that is indicative of the $F{{e}^{2+}}$ ion is ferrous. Keep this in mind while answering the questions.
Complete step by step answer:
First, we should look at the oxidation states of ions involved in the making of this molecule. The word ferric indicates that the oxidation state of the $Fe$ ion is +3 and the word sulphate indicates that the formula of the ion present is $S{{O}_{4}}$ we know that this ion has an oxidation state of -2 so we can rule out ‘option B’ since it has the $S{{O}_{3}}$ ion. We know that the overall charge on the molecule is 0, so we can balance the charges to find the number of each ion involved in the molecule.
We see by trial and error method by considering all the options given that only in option ‘D. \[F{{e}_{2}}{{\left( S{{O}_{4}} \right)}_{3}}\]’ the overall charge comes out to be 0 (It is +1 in option A and -1 in option C).
The structure of Ferric sulphate is given below:
Hence, the answer is. \[F{{e}_{2}}{{\left( S{{O}_{4}} \right)}_{3}}\]’.
So, the correct answer is “Option B”.
Note: Remember that when the ion $S{{O}_{3}}^{2-}$ is involved, the word sulphite will be used in the naming of the molecule. The word that is indicative of the $F{{e}^{2+}}$ ion is ferrous. Keep this in mind while answering the questions.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
Mark and label the given geoinformation on the outline class 11 social science CBSE
When people say No pun intended what does that mea class 8 english CBSE
Name the states which share their boundary with Indias class 9 social science CBSE
Give an account of the Northern Plains of India class 9 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Trending doubts
Difference Between Plant Cell and Animal Cell
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Which are the Top 10 Largest Countries of the World?
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Choose the antonym of the word given below Furious class 9 english CBSE
How do you graph the function fx 4x class 9 maths CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Change the following sentences into negative and interrogative class 10 english CBSE