![SearchIcon](https://vmkt.vedantu.com/vmkt/PROD/png/bdcdbbd8-08a7-4688-98e6-4aa54e5e0800-1733305962725-4102606384256179.png)
Fill up the blank with suitable
Acceleration due to gravity independent of ________
Answer
504.3k+ views
- Hint – Here we will proceed by using the concept of Newton’s second law of motion that is $F = m \times a$ (force $ = $ mass $ \times $acceleration). Acceleration $ = \dfrac{{Force}}{{Mass}}$.
Complete step-by-step solution -
Acceleration due to gravity is independent of mass. These two quantities are independent of each other. Light objects accelerate more slowly than heavy objects when forces other than gravity are also at work. In this case the object is falling but is not considered as a free fall.
A body of mass m falling under the influence of gravity has a force given as –
$F = \dfrac{{GMm}}{{{R^2}}}$
Here, G is gravitational constant
M- mass of 1st body
m-mass of 2nd body
R- distance between two bodies.
Here, M is the mass of Earth and R is the radius of Earth.
Also this force is the weight of the body which is given as
$F = mg$ $ \to $ weight
Thus, we get
$\dfrac{{GMm}}{{{R^2}}} = mg$
$g = \dfrac{{GM}}{{{R^2}}}$
All these are constants and do not change.
So we can say that
Value of g remains constant. G is a universal constant.
It does not depend upon the mass of the body falling.
Note – Whenever we come up with this type of question, one must know that acceleration due to gravity does not depend upon the mass of the object. Then we write the formula of force and calculate the acceleration due to gravity. (Here by using the formula we calculate acceleration due to gravity is independent of mass).
Complete step-by-step solution -
Acceleration due to gravity is independent of mass. These two quantities are independent of each other. Light objects accelerate more slowly than heavy objects when forces other than gravity are also at work. In this case the object is falling but is not considered as a free fall.
A body of mass m falling under the influence of gravity has a force given as –
$F = \dfrac{{GMm}}{{{R^2}}}$
Here, G is gravitational constant
M- mass of 1st body
m-mass of 2nd body
R- distance between two bodies.
Here, M is the mass of Earth and R is the radius of Earth.
Also this force is the weight of the body which is given as
$F = mg$ $ \to $ weight
Thus, we get
$\dfrac{{GMm}}{{{R^2}}} = mg$
$g = \dfrac{{GM}}{{{R^2}}}$
All these are constants and do not change.
So we can say that
Value of g remains constant. G is a universal constant.
It does not depend upon the mass of the body falling.
Note – Whenever we come up with this type of question, one must know that acceleration due to gravity does not depend upon the mass of the object. Then we write the formula of force and calculate the acceleration due to gravity. (Here by using the formula we calculate acceleration due to gravity is independent of mass).
Recently Updated Pages
Glucose when reduced with HI and red Phosphorus gives class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The highest possible oxidation states of Uranium and class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Find the value of x if the mode of the following data class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which of the following can be used in the Friedel Crafts class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
A sphere of mass 40 kg is attracted by a second sphere class 11 physics CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Statement I Reactivity of aluminium decreases when class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
10 examples of friction in our daily life
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Prokaryotic Cells and Eukaryotic Cells
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
State and prove Bernoullis theorem class 11 physics CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What organs are located on the left side of your body class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
How many valence electrons does nitrogen have class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)