Answer
Verified
429.9k+ views
Hint: An extraneous solution is a solution value of the variable in the equations, that is found by solving the given equation algebraically but it is not a solution of the given equation. We get these types of solutions sometimes when we solve radical equations. Radical equations are equations in which the variable is under a radical. To find the solution of a radical equation, we need to take the radical expression to one side of the equations. If there is more than one radical expression, take one at a time.
Complete step by step answer:
Let’s take an example of radical expression \[x+1=\sqrt{7x+15}\]. We need to solve this equation. Squaring both sides of the above equation, we get
\[\Rightarrow {{\left( x+1 \right)}^{2}}={{\left( \sqrt{7x+15} \right)}^{2}}\]
simplifying the above equation, we get
\[\begin{align}
& \Rightarrow {{x}^{2}}+2x+1=7x+15 \\
& \Rightarrow {{x}^{2}}-5x-14=0 \\
\end{align}\]
We can find the roots of the above quadratic equation, by using the formula method, as follows
\[\begin{align}
& \Rightarrow x=\dfrac{-(-5)\pm \sqrt{{{\left( -5 \right)}^{2}}-4(1)(-14)}}{2(1)} \\
& \Rightarrow x=\dfrac{5\pm \sqrt{81}}{2} \\
& \Rightarrow x=\dfrac{5\pm 9}{2} \\
\end{align}\]
\[\Rightarrow x=\dfrac{5+9}{2}=\dfrac{14}{2}\] or \[x=\dfrac{5-9}{2}=\dfrac{-4}{2}\]
\[\therefore x=7\] or \[x=-2\]
But if we substitute \[x=-2\] in the equation, we get
\[\begin{align}
& -2+1=\sqrt{7(-2)+15} \\
& \Rightarrow -1=1 \\
\end{align}\]
Which is not correct. Hence, \[x=-2\] is not a solution of the given radical equation. Thus \[x=-2\] is an extraneous solution for the given equation.
Note: We should know when an extraneous solution occurs. Extraneous solutions of an equation are solutions that occur when a radical expression that has an even index, such as 2, is raised to its power to find the solution of an equation.
In the above example, as the radical power has an even index, we get \[x=-2\] as an extraneous solution of the equation.
Complete step by step answer:
Let’s take an example of radical expression \[x+1=\sqrt{7x+15}\]. We need to solve this equation. Squaring both sides of the above equation, we get
\[\Rightarrow {{\left( x+1 \right)}^{2}}={{\left( \sqrt{7x+15} \right)}^{2}}\]
simplifying the above equation, we get
\[\begin{align}
& \Rightarrow {{x}^{2}}+2x+1=7x+15 \\
& \Rightarrow {{x}^{2}}-5x-14=0 \\
\end{align}\]
We can find the roots of the above quadratic equation, by using the formula method, as follows
\[\begin{align}
& \Rightarrow x=\dfrac{-(-5)\pm \sqrt{{{\left( -5 \right)}^{2}}-4(1)(-14)}}{2(1)} \\
& \Rightarrow x=\dfrac{5\pm \sqrt{81}}{2} \\
& \Rightarrow x=\dfrac{5\pm 9}{2} \\
\end{align}\]
\[\Rightarrow x=\dfrac{5+9}{2}=\dfrac{14}{2}\] or \[x=\dfrac{5-9}{2}=\dfrac{-4}{2}\]
\[\therefore x=7\] or \[x=-2\]
But if we substitute \[x=-2\] in the equation, we get
\[\begin{align}
& -2+1=\sqrt{7(-2)+15} \\
& \Rightarrow -1=1 \\
\end{align}\]
Which is not correct. Hence, \[x=-2\] is not a solution of the given radical equation. Thus \[x=-2\] is an extraneous solution for the given equation.
Note: We should know when an extraneous solution occurs. Extraneous solutions of an equation are solutions that occur when a radical expression that has an even index, such as 2, is raised to its power to find the solution of an equation.
In the above example, as the radical power has an even index, we get \[x=-2\] as an extraneous solution of the equation.
Recently Updated Pages
10 Examples of Evaporation in Daily Life with Explanations
10 Examples of Diffusion in Everyday Life
1 g of dry green algae absorb 47 times 10 3 moles of class 11 chemistry CBSE
If x be real then the maximum value of 5 + 4x 4x2 will class 10 maths JEE_Main
If the coordinates of the points A B and C be 443 23 class 10 maths JEE_Main
What happens when dilute hydrochloric acid is added class 10 chemistry JEE_Main
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Which are the Top 10 Largest Countries of the World?
How do you graph the function fx 4x class 9 maths CBSE
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
In the tincture of iodine which is solute and solv class 11 chemistry CBSE
Why is there a time difference of about 5 hours between class 10 social science CBSE