Answer
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Hint: We know that the greatest 5 digit number is 99999, but we have to find the greatest 5 digits number that will give remainder of 5, when divided by 8 and 9 respectively. For this we take L.C.M of 8 and 9 and divide the number 99999.
Complete step-by-step answer:
We know that the greatest 5 digit number is 99999.
Now, we have to find the greatest 5 digit number that will give a remainder of 5, when divided by 8 and 9 respectively.
So, L.C.M of 8 and 9 is shown below: -
\[\begin{align}
& 8=2\times 2\times 2 \\
& 9=3\times 3 \\
\end{align}\]
L.C.M = \[2\times 2\times 2\times 3\times 3=72\].
Hence, the L.C.M of 8 and 9 is 72.
Now, we will find the greatest 5 – digit number divisible by 8 and 9 by dividing 99999 by 72.
The division of 99999 by 72 is shown as below: -
\[72\overset{1388}{\overline{\left){\begin{align}
& 99999 \\
& \underline{-72} \\
& 279 \\
& \underline{-216} \\
& 639 \\
& \underline{-576} \\
& 639 \\
& \underline{-576} \\
& 63 \\
\end{align}}\right.}}\]
So, from the above division we get,
Quotient = 1388
Remainder = 63
So, the greatest 5 – digit number divisible by 8 and 9 = 99999 – 63 = 99936.
Required number = 99936 + 5 = 99941
\[\because \] We have been given that a remainder of 5 is there when the number is divided by 8 and 9 respectively. So, we add the remainder to the number which is divisible by 8 and 9.
Therefore, we get the greatest number of 5 digits, that will give a remainder of 5, when divided by 8 and 9 respectively is 99941.
Note: Just be careful while doing calculation as there is a chance that you might make a mistake and you will get the incorrect answer. Most students make the mistake of adding the remainder to 99999 instead of subtracting it. Also, they may forget to add 5 to 99936 and often write 99936 as the final answer.
Complete step-by-step answer:
We know that the greatest 5 digit number is 99999.
Now, we have to find the greatest 5 digit number that will give a remainder of 5, when divided by 8 and 9 respectively.
So, L.C.M of 8 and 9 is shown below: -
\[\begin{align}
& 8=2\times 2\times 2 \\
& 9=3\times 3 \\
\end{align}\]
L.C.M = \[2\times 2\times 2\times 3\times 3=72\].
Hence, the L.C.M of 8 and 9 is 72.
Now, we will find the greatest 5 – digit number divisible by 8 and 9 by dividing 99999 by 72.
The division of 99999 by 72 is shown as below: -
\[72\overset{1388}{\overline{\left){\begin{align}
& 99999 \\
& \underline{-72} \\
& 279 \\
& \underline{-216} \\
& 639 \\
& \underline{-576} \\
& 639 \\
& \underline{-576} \\
& 63 \\
\end{align}}\right.}}\]
So, from the above division we get,
Quotient = 1388
Remainder = 63
So, the greatest 5 – digit number divisible by 8 and 9 = 99999 – 63 = 99936.
Required number = 99936 + 5 = 99941
\[\because \] We have been given that a remainder of 5 is there when the number is divided by 8 and 9 respectively. So, we add the remainder to the number which is divisible by 8 and 9.
Therefore, we get the greatest number of 5 digits, that will give a remainder of 5, when divided by 8 and 9 respectively is 99941.
Note: Just be careful while doing calculation as there is a chance that you might make a mistake and you will get the incorrect answer. Most students make the mistake of adding the remainder to 99999 instead of subtracting it. Also, they may forget to add 5 to 99936 and often write 99936 as the final answer.
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