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Find the interquartile range of the o-give.
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Answer
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Hint: We observe the given o-give and find that we are given the median, the lower quartile Q1, the upper quartile Q3. We use the fact that interquartile range IQR is different from upper and lower quartile which is given by IQR=Q3Q1.

Complete step-by-step solution:
We know that cumulative frequency fn of a class interval Ic is sum of frequency of In and frequencies of all class intervals before In which means
fc=i=1cfi
We know that ogive is a free hand-drawn curve to determine how much data values lie above or below a particular value in the sample population. The upper limits of the class interval are marked on the horizontal axis of the graph. The absolute or cumulative relative frequencies are marked right above with respect to the vertical axis and a plot is drawn with freehand.
We know in order statistics that the median is the middle of the data sample which separates the upper half and the lower half of the data in ascending order. It means 50% of the data lie below the median.
 The quartiles are quantiles which divide the data into four parts. The first or lower quartile is the middle value between the smallest value in the data and the median. It is denoted by Q1. The second quartile is the median itself and is denoted by Q2. The third or highest quartile is the middle value between the median and the highest value and is denoted by Q3. The interquartile range IQR is the difference between the highest and lowest quartile. So we have
r=Q3Q1
We observe the given o-give and find that we are given the lowest quartile Q1=11.5, the median Q2=21 and highest quartile Q3=27.7. So the interquartile range is IQR=Q3Q1=27.711.5=16.2

Note: We note that the quantile is a data point, which divides the data into equal parts. We get only one quantile called median when we divide the data into two equal parts. The percentile like quartile divides the data into a hundred parts.