
Find the roots of the equation ${x^2} + 7x + 12 = 0$ by using the formula.
Answer
521.4k+ views
Hint- Here, we will proceed with the help of factorization as well as discriminant formula to solve for the two roots of the given quadratic equation. For discriminant method we will apply the general formula $x = \dfrac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}$ for any quadratic equation $a{x^2} + bx + c = 0$.
Complete step-by-step answer:
Given quadratic equation in variable x is ${x^2} + 7x + 12 = 0{\text{ }} \to {\text{(1)}}$
Here, we can solve this quadratic equation with the help of factorization method. The given quadratic equation can be written as
$ \Rightarrow {x^2} + 7x + 12 = 0 \Rightarrow {x^2} + 3x + 4x + 12 = 0 \Rightarrow x\left( {x + 3} \right) + 4\left( {x + 3} \right) = 0 \Rightarrow \left( {x + 3} \right)\left( {x + 4} \right) = 0$
Either $
\left( {x + 3} \right) = 0 \\
\Rightarrow x = - 3 \\
$ or $
\left( {x + 4} \right) = 0 \\
\Rightarrow x = - 4 \\
$
Hence, the two roots of the given quadratic equation are -3 and -4.
We can also solve the given quadratic equation by using the discriminant method.
For any general quadratic equation $a{x^2} + bx + c = 0{\text{ }} \to {\text{(2)}}$
According to discriminant method, the roots of this quadratic equation is given by
$x = \dfrac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}{\text{ }} \to {\text{(3)}}$
By comparing equations (1) and (2), we get
a=1, b=7 and c=12
Using the formula given by equation (3), the roots of the given quadratic equation are given by
\[x = \dfrac{{ - 7 \pm \sqrt {{{\left( 7 \right)}^2} - 4 \times 1 \times 12} }}{{2 \times 1}} = \dfrac{{ - 7 \pm \sqrt {49 - 48} }}{2} = \dfrac{{ - 7 \pm \sqrt 1 }}{2} = \dfrac{{ - 7 \pm 1}}{2}\]
Either \[x = \dfrac{{ - 7 + 1}}{2} = \dfrac{{ - 6}}{2} = - 3\] or \[x = \dfrac{{ - 7 - 1}}{2} = \dfrac{{ - 8}}{2} = - 4\]
So, the two roots of the given quadratic equation are -3 and -4.
Clearly, we are getting the same results from both factorization method and discriminant method.
Note- In these types of problems, we can use either factorization method or discriminant method to obtain the roots of the given quadratic equation. But discriminant method is usually adopted because it is an easier method as compared to factorization method for finding the roots of the given quadratic equation.
Complete step-by-step answer:
Given quadratic equation in variable x is ${x^2} + 7x + 12 = 0{\text{ }} \to {\text{(1)}}$
Here, we can solve this quadratic equation with the help of factorization method. The given quadratic equation can be written as
$ \Rightarrow {x^2} + 7x + 12 = 0 \Rightarrow {x^2} + 3x + 4x + 12 = 0 \Rightarrow x\left( {x + 3} \right) + 4\left( {x + 3} \right) = 0 \Rightarrow \left( {x + 3} \right)\left( {x + 4} \right) = 0$
Either $
\left( {x + 3} \right) = 0 \\
\Rightarrow x = - 3 \\
$ or $
\left( {x + 4} \right) = 0 \\
\Rightarrow x = - 4 \\
$
Hence, the two roots of the given quadratic equation are -3 and -4.
We can also solve the given quadratic equation by using the discriminant method.
For any general quadratic equation $a{x^2} + bx + c = 0{\text{ }} \to {\text{(2)}}$
According to discriminant method, the roots of this quadratic equation is given by
$x = \dfrac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}{\text{ }} \to {\text{(3)}}$
By comparing equations (1) and (2), we get
a=1, b=7 and c=12
Using the formula given by equation (3), the roots of the given quadratic equation are given by
\[x = \dfrac{{ - 7 \pm \sqrt {{{\left( 7 \right)}^2} - 4 \times 1 \times 12} }}{{2 \times 1}} = \dfrac{{ - 7 \pm \sqrt {49 - 48} }}{2} = \dfrac{{ - 7 \pm \sqrt 1 }}{2} = \dfrac{{ - 7 \pm 1}}{2}\]
Either \[x = \dfrac{{ - 7 + 1}}{2} = \dfrac{{ - 6}}{2} = - 3\] or \[x = \dfrac{{ - 7 - 1}}{2} = \dfrac{{ - 8}}{2} = - 4\]
So, the two roots of the given quadratic equation are -3 and -4.
Clearly, we are getting the same results from both factorization method and discriminant method.
Note- In these types of problems, we can use either factorization method or discriminant method to obtain the roots of the given quadratic equation. But discriminant method is usually adopted because it is an easier method as compared to factorization method for finding the roots of the given quadratic equation.
Recently Updated Pages
Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Trending doubts
Truly whole mankind is one was declared by the Kannada class 10 social science CBSE

Explain the three major features of the shiwaliks class 10 social science CBSE

What are the public facilities provided by the government? Also explain each facility

Question An example of homologous organs is a Our arm class 10 biology CBSE

What is Commercial Farming ? What are its types ? Explain them with Examples

What is the past tense of read class 10 english CBSE
