![SearchIcon](https://vmkt.vedantu.com/vmkt/PROD/png/bdcdbbd8-08a7-4688-98e6-4aa54e5e0800-1733305962725-4102606384256179.png)
Find the tension in the string.
![seo images](https://www.vedantu.com/question-sets/f5e15abb-f5e8-4528-bb76-377bc6b095733700083727691020122.png)
Answer
397.2k+ views
Hint: Tension is nothing but the force that acts in an axial direction. we know that the tensile force and compressive force. The tensile force means the stretching force acting on the material. The object is hung by ropes, strings, and chains, the tensile force acts in an axial direction in the ropes or strings due to the mass of the object. The tensions are to be measured here in the problem.
Formula used:
For the object, which is hung by the string and is in stationary (not moving)
The tension in the string $T = W$, $\left( {W = m \times g} \right)$
$T = m \times g$
Where T- the tension in the string
$W$- weight of the object hung by the string (N)
\[m\] - the mass of the object hung by the string
\[g\] - acceleration due to gravity $\left( {g = 9.81 \times \dfrac{m}{{{s^2}}}} \right)$
Complete answer:
We are going to find the tensions of the string $T_1,T_2$.
To find the tension $T_1$,${m_1} = 2kg$
$T_1 = {m_1} \times g$
$T_1 = 2 \times 9.81$
$T_1 = 19.62N$
The tension of the string $T_1 = 19.62N$
To find the tension $T_2,{m_2} = 5kg$
$T_2 = {m_2} \times g$
$T_2 = 5 \times 9.81$
$T_2 = 49.05N$
The tension of the string $T_2 = 49.05N$
From the above calculations, we found that the tensions of the string as a result.
$T_1 = 19.62N$,$T_2 = 49.05N$
Note: For example, if we stretch the rubber bands, it undergoes tensile force and causes tension in the rubber band. The tensile strength of the material is defined as the ability of the material by which it can sustain the maximum amount of load when being stretched. These calculations can be used in constructions and manufacturing industrial components, The tension of the string, rope, or chain during acceleration is $T = W \pm m.a$. For the object goes upward,$T = W + m.a$and for the object goes downward, $T = W - m.a$.
Formula used:
For the object, which is hung by the string and is in stationary (not moving)
The tension in the string $T = W$, $\left( {W = m \times g} \right)$
$T = m \times g$
Where T- the tension in the string
$W$- weight of the object hung by the string (N)
\[m\] - the mass of the object hung by the string
\[g\] - acceleration due to gravity $\left( {g = 9.81 \times \dfrac{m}{{{s^2}}}} \right)$
Complete answer:
We are going to find the tensions of the string $T_1,T_2$.
To find the tension $T_1$,${m_1} = 2kg$
$T_1 = {m_1} \times g$
$T_1 = 2 \times 9.81$
$T_1 = 19.62N$
The tension of the string $T_1 = 19.62N$
To find the tension $T_2,{m_2} = 5kg$
$T_2 = {m_2} \times g$
$T_2 = 5 \times 9.81$
$T_2 = 49.05N$
The tension of the string $T_2 = 49.05N$
From the above calculations, we found that the tensions of the string as a result.
$T_1 = 19.62N$,$T_2 = 49.05N$
Note: For example, if we stretch the rubber bands, it undergoes tensile force and causes tension in the rubber band. The tensile strength of the material is defined as the ability of the material by which it can sustain the maximum amount of load when being stretched. These calculations can be used in constructions and manufacturing industrial components, The tension of the string, rope, or chain during acceleration is $T = W \pm m.a$. For the object goes upward,$T = W + m.a$and for the object goes downward, $T = W - m.a$.
Recently Updated Pages
Master Class 11 Accountancy: Engaging Questions & Answers for Success
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Glucose when reduced with HI and red Phosphorus gives class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The highest possible oxidation states of Uranium and class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Find the value of x if the mode of the following data class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which of the following can be used in the Friedel Crafts class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
A sphere of mass 40 kg is attracted by a second sphere class 11 physics CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Define least count of vernier callipers How do you class 11 physics CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The combining capacity of an element is known as i class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Find the image of the point 38 about the line x+3y class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Can anyone list 10 advantages and disadvantages of friction
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Distinguish between Mitosis and Meiosis class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)