Question

Find the value of $$[(-A)+(-B)]$$ if the values A and B are 99 and 11 respectively.
(a)-100
(b)-88
(c)-110
(d)-111

Answer 1

Hint: To solve this question we will substitute the values of A as A=99 and B as B=11 in the given equation $$[(-A)+(-B)]$$. With the help of substitution of the variables we will proceed to find a solution of the given expression.

Complete step-by-step answer:
We are given the values of A and B in the question as A=99 and B=11 respectively, we just have to substitute the values of A and B in the equation $$[(-A)+(-B)]$$ to obtain the result.
Remember that adding two negative numbers gives the sum as a negative number again. Here we are given A and B both positive but we have a minus sign in front of both of them in the expression $$[(-A)+(-B)]$$ So if we add them we will again be getting a negative number.

 After inserting the value of A=99 the given equation becomes
$$[(-A)+(-B)]=[(-99)+(-B)]$$
Now similarly inserting the value of B=11 the above equation becomes
$$[(-A)+(-B)]=[(-99)+(-11)]$$

After solving the inner brackets and adding the negative integers we get
$$\begin{array}{rl}& \Rightarrow [(-A)+(-B)]=[-99-11]\\ & \\ & \Rightarrow [(-A)+(-B)]=[-110]\end{array}$$

So, we obtain the answer of the above equation as $$[(-A)+(-B)]=-110$$ i.e. option(c) is correct.

Note: While solving the equation we should take care of the negative value of both the numbers A and B and remember that adding two negative numbers gives a negative number again. Here both A and B are positive but because of the use of minus sign in front of them the answer is coming to be negative.