Answer
Verified
497.4k+ views
Hint: In order to solve this question we have to convert tan in terms of $\cot {\text{ }} as \left[ {{\text{ tan}}\theta = \left( {\cot {{90}^ \circ } - \theta } \right)} \right]$ by doing so we will get both sides in terms of cot.
Complete step-by-step answer:
Now, we have given that
If $\tan 2A = \cot \left( {A - {{18}^ \circ }} \right)$
And 2A is an acute angle.
Now we have to find the value of A.
Now this question is related to trigonometric.
Ratios of complementary angles,
Complementary Angles- Two angles are said to be complementary if their sum is equal to ${90^ \circ }$.
Also we know that,
$\cot \left( {{{90}^ \circ } - x} \right) = \tan x$ ------(1)
According to the given question,
$\tan 2A = \cot \left( {A - {{18}^ \circ }} \right)$
Since, $2A$ is an acute angle thus from equation(1) we get,
$\cot \left( {{{90}^ \circ } - 2A} \right) = \cot \left( {A - {{18}^ \circ }} \right)$
Now, eliminate cot from both sides, we get
${90^ \circ } - 2A = A - {18^ \circ }$
$\Rightarrow$ $3A = {108^ \circ }$
$\Rightarrow$ $A = \dfrac{{{{108}^ \circ }}}{3}$
$\Rightarrow$ $A = {36^ \circ }$
Thus, the value of A is ${36^ \circ }$.
Note: Whenever we face such types of questions, the key concept is that we must covert tan in terms of cot or vice versa. It is clearly visible that here $2A$ represents an acute angle. First we will use the identity $\tan \theta = \cot \left( {{{90}^ \circ } - \theta } \right)$ then eliminate cot (or tan) then by simplifying the equations we will get our required answer.
Complete step-by-step answer:
Now, we have given that
If $\tan 2A = \cot \left( {A - {{18}^ \circ }} \right)$
And 2A is an acute angle.
Now we have to find the value of A.
Now this question is related to trigonometric.
Ratios of complementary angles,
Complementary Angles- Two angles are said to be complementary if their sum is equal to ${90^ \circ }$.
Also we know that,
$\cot \left( {{{90}^ \circ } - x} \right) = \tan x$ ------(1)
According to the given question,
$\tan 2A = \cot \left( {A - {{18}^ \circ }} \right)$
Since, $2A$ is an acute angle thus from equation(1) we get,
$\cot \left( {{{90}^ \circ } - 2A} \right) = \cot \left( {A - {{18}^ \circ }} \right)$
Now, eliminate cot from both sides, we get
${90^ \circ } - 2A = A - {18^ \circ }$
$\Rightarrow$ $3A = {108^ \circ }$
$\Rightarrow$ $A = \dfrac{{{{108}^ \circ }}}{3}$
$\Rightarrow$ $A = {36^ \circ }$
Thus, the value of A is ${36^ \circ }$.
Note: Whenever we face such types of questions, the key concept is that we must covert tan in terms of cot or vice versa. It is clearly visible that here $2A$ represents an acute angle. First we will use the identity $\tan \theta = \cot \left( {{{90}^ \circ } - \theta } \right)$ then eliminate cot (or tan) then by simplifying the equations we will get our required answer.
Recently Updated Pages
Fill in the blanks with suitable prepositions Break class 10 english CBSE
Fill in the blanks with suitable articles Tribune is class 10 english CBSE
Rearrange the following words and phrases to form a class 10 english CBSE
Select the opposite of the given word Permit aGive class 10 english CBSE
Fill in the blank with the most appropriate option class 10 english CBSE
Some places have oneline notices Which option is a class 10 english CBSE
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
How do you graph the function fx 4x class 9 maths CBSE
When was Karauli Praja Mandal established 11934 21936 class 10 social science CBSE
Which are the Top 10 Largest Countries of the World?
What is the definite integral of zero a constant b class 12 maths CBSE
Why is steel more elastic than rubber class 11 physics CBSE
Distinguish between the following Ferrous and nonferrous class 9 social science CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE