Question

Find the value of \[\left( {{3^0} - {4^0}} \right) \times {5^2}\]:

Answer 1

Hint: To solve this question first we simplify the powers that are given in each term after that we use the BODMAS rule to simplify forward. This rule gives precedence to mathematical operators so according to that we solve the bracket and then after we simplify the multiplication and that, we get the final answer.

Complete answer:
To find,
The value of \[\left( {{3^0} - {4^0}} \right) \times {5^2}\]
Let the value of the expression
\[x = \left( {{3^0} - {4^0}} \right) \times {5^2}\].
To solve further first we simplify the power of each and every term.
We know that if power on any number is zero then the value of that expression is 1
Using this rule
\[x = \left( {1 - 1} \right) \times {5^2}\]
Now solving the power on \[5\]. We know that \[{5^2}\] is \[25\]
 \[x = \left( {1 - 1} \right) \times 25\]
Now for further solving we use the BODMAS rule, this rule will give the order of solving the mathematical operators the order is “bracket”, “of”, “division”, “multiplication”, “addition”, “subtraction”.
So first we solve the bracket part
\[x = 0 \times 25\]
Now after the next term of order is “of” but “of” is not in the expression so we come to multiplication.
If we multiply any term with \[0\] then the answer is also \[0\].
\[x = 0\]
Final answer:
The value of the given expression \[\left( {{3^0} - {4^0}} \right) \times {5^2}\] is
\[ \Rightarrow x = 0\].

Note:
To solve this type of question we have to know the squares, cubes, and the number having power equal to \[0\]. And after solving the power, we have to do further calculations and those calculations are based on the rule BODMAS. The rule tells us the precedence of solving the mathematical operators. You may commit a mistake in applying the BODMAS rule in the simple expression.