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How do you find which quadrant each question is referring to if 0<a<π2 and 3π2<a<2π?

Answer
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Hint: We explain the central angle around a point. Then we discuss the algebraic and geometric versions of the quadrants. We also find different quadrants and their characteristics. Then we find the solutions for the angles 0<a<π2 and 3π2<a<2π.

Complete step by step answer:
The central angle around a point is always equal to 360.
The total angle is divided into four parts or quadrant as they are called. These quadrants are named in roman numerals of I,II,III,IV.
In case of algebraic sense these quadrants give the signs of the x and y coordinates.
These quadrants are also called as the first, second, third and fourth quadrant.
The respective signs for the coordinates of (x,y) will be (+,+),(,+),(,),(+,) respectively for the quadrants.
Now we look for the geometric side of the quadrants where we deal with the angle of the trigonometric ratios.
The total circular angle of 2π can be divided into four parts. Each part is of π2.
Therefore, the first quadrant is the interval of (0,π2). The second quadrant is the interval of (π2,π). The third quadrant is the interval of (π,3π2). The fourth quadrant is the interval of (3π2,2π). The 0,π2,π,3π2 indicates the axes.
Now we find for the quadrants 0<a<π2 and 3π2<a<2π.
When the angle 0<a<π2, the quadrant is first and when the angle 3π2<a<2π, the quadrant is fourth.

Note:
We can also represent the quadrants with respect to the image form of both algebraic and geometric versions.
seo images

The rotation of the coordinates happens anti-clockwise.
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