Question

What is the formula for tin (IV) nitride?

Answer 1

Hint: Nitride ion is an ion formed by the formation of bonds between three nitrogen. Nitride has the total of negative three charges. Nitrogen belongs to the p block and is a very important element which is the most abundant in our atmosphere. Nitrogen has a total of fourteen electrons.

Complete answer:
Nitride ion is an ion formed by the formation of bonds between three nitrogen. Nitride has a total of negative three charges. Nitrogen belongs to the p block and is a very important element which is the most abundant in our atmosphere. Nitrogen has a total of fourteen electrons.
Tin belongs to the d block element; it has the atomic number of fifty. It has the electronic configuration of $[Kr]5{s^2}4{d^{10}}5{p^2}$
Here we can see that the electrons in the last orbital p are only two and both of them are unpaired, we get to know that by the fact that the most stable electronic configuration of an electron in the orbitals are either all paired or all unpaired.
Nitride is a very strong ligand and has a very high electronic charge on it which we attack a d block element like hybridises its orbital and for tin to readily react with, it loses four electrons out of its last orbital.
The oxidation state possessed by tin is $ + 4$and the oxidation state possessed by nitride is $ + 3$.
These atoms attack each other and form a compound $S{n_3}{N_4}$.
The formula for tin (IV) nitride is $S{n_3}{N_4}$.

Note:
Titanium nitride is a refractory compound with high microhardness and chemical and thermal stability. Tin has a variety of applications: as a component in special refractories and sermet's, as a material for crucibles for anoxic casting of metals, and as a precursor for wear–resistant and decorative “gold-like” coating.