
From a well shuffled pack of $52$ cards , a cards is picked at random , find the probability that the card picked
a. Is either a queen or a red card
(i) Depict the probability through venn diagram
b. Neither jack or spade
(ii) Depict the probability through venn diagram
Answer
573.6k+ views
Hint:
Probability of event is equal to $\dfrac{{{\text{Favourable outcomes }}}}{{{\text{Total number of outcomes }}}}$ In the part (i) Total number of red cards in a deck of card is $13 + 13 = 26$ ,Total queens are $4$ in which $2$ are red and $2$ are black.
In the part (ii) Total number of Spade cards in a deck of cards is $13$ Total Jacks are $4$ in which $1$ are spade and $3$ are non- spade.
Complete step by step solution:
In this question we have to find the probability of a well shuffled pack of $52$ cards ,
In the part (i)
It is given that the Is either a queen or a red card So ,
Total number of cards in a pack $52$
Total number of red cards in a deck of card is $13 + 13 = 26$
Total queens are $4$ in which $2$ are red and $2$ are black.
Total number of red cards and queens is $26 + 2 = 28$
Now for the probability of event = $\dfrac{{{\text{Favourable outcomes }}}}{{{\text{Total number of outcomes }}}}$
Favourable outcomes = $28$ Total number of outcomes =$52$
Probability = $\dfrac{{28}}{{52}}$ = $0.5384$
Now for the venn diagram
So from the venn diagram Probability is equal $\dfrac{{{\text{Shaded Region }}}}{{{\text{Total area}}}}$ that is equal to $\dfrac{{28}}{{52}}$= $0.5384$
In the part (ii) Probability we have to find neither jack nor spade
Total number of cards in a pack $52$
Total number of Spade cards in a deck of card is $13$
Total Jacks are $4$ in which $1$ are spade and $3$ are non- spade
Total number of spade card + Jack cards is $13 + 3 = 16$
Neither spade nor Jack cards = $52 - 16 = 36$
Now for the probability of event = $\dfrac{{{\text{Favourable outcomes }}}}{{{\text{Total number of outcomes }}}}$
Favourable outcomes = $36$ Total number of outcomes =$52$
Probability = $\dfrac{{36}}{{52}}$ = $0.72$
Now for the venn diagram
So from the venn diagram Probability is equal $\dfrac{{{\text{Shaded Region }}}}{{{\text{Total area}}}}$ that is equal to $\dfrac{{36}}{{52}}$= $0.72$
Note:
In a deck of cards , All cards are divided into 4 suits. There are two black suits — spades and clubs and two red suits — hearts and diamonds.
Probability of any event always lies between $0$ to $1$. If your answer comes apart from this then cross check it.
Probability of event is equal to $\dfrac{{{\text{Favourable outcomes }}}}{{{\text{Total number of outcomes }}}}$ In the part (i) Total number of red cards in a deck of card is $13 + 13 = 26$ ,Total queens are $4$ in which $2$ are red and $2$ are black.
In the part (ii) Total number of Spade cards in a deck of cards is $13$ Total Jacks are $4$ in which $1$ are spade and $3$ are non- spade.
Complete step by step solution:
In this question we have to find the probability of a well shuffled pack of $52$ cards ,
In the part (i)
It is given that the Is either a queen or a red card So ,
Total number of cards in a pack $52$
Total number of red cards in a deck of card is $13 + 13 = 26$
Total queens are $4$ in which $2$ are red and $2$ are black.
Total number of red cards and queens is $26 + 2 = 28$
Now for the probability of event = $\dfrac{{{\text{Favourable outcomes }}}}{{{\text{Total number of outcomes }}}}$
Favourable outcomes = $28$ Total number of outcomes =$52$
Probability = $\dfrac{{28}}{{52}}$ = $0.5384$
Now for the venn diagram
So from the venn diagram Probability is equal $\dfrac{{{\text{Shaded Region }}}}{{{\text{Total area}}}}$ that is equal to $\dfrac{{28}}{{52}}$= $0.5384$
In the part (ii) Probability we have to find neither jack nor spade
Total number of cards in a pack $52$
Total number of Spade cards in a deck of card is $13$
Total Jacks are $4$ in which $1$ are spade and $3$ are non- spade
Total number of spade card + Jack cards is $13 + 3 = 16$
Neither spade nor Jack cards = $52 - 16 = 36$
Now for the probability of event = $\dfrac{{{\text{Favourable outcomes }}}}{{{\text{Total number of outcomes }}}}$
Favourable outcomes = $36$ Total number of outcomes =$52$
Probability = $\dfrac{{36}}{{52}}$ = $0.72$
Now for the venn diagram
Note:
In a deck of cards , All cards are divided into 4 suits. There are two black suits — spades and clubs and two red suits — hearts and diamonds.
Probability of any event always lies between $0$ to $1$. If your answer comes apart from this then cross check it.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

What are the major means of transport Explain each class 12 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

Why cannot DNA pass through cell membranes class 12 biology CBSE

Differentiate between insitu conservation and exsitu class 12 biology CBSE

Draw a neat and well labeled diagram of TS of ovary class 12 biology CBSE

