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Give reasons for the following:
Aniline does not undergo Friedel-Crafts reaction:

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Answer
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Hint: We have to know that the Friedel-Crafts response is a natural coupling response including an electrophilic fragrant replacement that is utilized for the connection of substituents to sweet-smelling rings. The two essential kinds of Friedel-Crafts responses are the alkylation and acylation responses.

Complete answer:
We have to see that Friedel-Crafts Alkylation alludes to the supplanting of a sweet-smelling proton with an alkyl bunch. This is done through an electrophilic assault on the sweet-smelling ring with the assistance of a carbocation. The Friedel-Crafts alkylation response is a technique for producing alkyl benzenes by utilizing alkyl halides as reactants.
We have to see that, Friedel-Crafts acylation response includes the expansion of an acyl gathering to a fragrant ring. Ordinarily, this is finished by utilizing a corrosive chloride $\left( {R - \left( {C = O} \right) - Cl} \right)$ and a Lewis corrosive impetus like, $AlC{l_3}$ . In a Friedel-Crafts acylation response, the fragrant ring is changed into a ketone.
When a Friedel-Crafts response is done within the sight of $AlC{l_3}$. However, $AlC{l_3}$ utilized as an impetus, and it is acidic in nature. Lewis corrosive while aniline is a solid Lewis base. Along these lines, aniline responds with $AlC{l_3}$ to shape a salt. Because of the positive charge on the N-particle, electrophilic replacement in the benzene ring is deactivated. Thus, aniline does not go through Friedel-Crafts response.

Note:
We have to know that an alkyl gathering can be added by an electrophile sweet-smelling replacement response called the Friedel-Crafts alkylation response to a benzene particle. The expansion of a methyl gathering to a benzene ring is one model. To frame a nonaromatic carbocation, the electrophile assaults the $\pi $ electron arrangement of the benzene ring.