Answer
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Hint:We know the meaning of resonating structure. From this we have to draw the all delocalization of lone pairs, negative and positive charge etc.
Complete step by step solution:
> We know that resonance is the way by which we describe delocalized electrons within certain molecules or polyatomic ions where the bonding can’t be expressed by a single Lewis formula or structure.
> Resonance structures: These are the set of two or more Lewis Structures that collectively describe the electronic bonding of a single polyatomic species including partial bonds and partial charges.
> Resonance structures are capable of describing delocalized electrons that cannot be expressed by a single Lewis formula with an integer number of covalent bonds.
> In case of\[N{{O}_{2}}\],it has one single bonded oxygen and one double bonded oxygen. Or we can say that this double bond delocalized. Below given are resonating structures of \[N{{O}_{2}}\]
> In case of\[{{N}_{2}}{{O}_{5}}\], it has two double bonded oxygens and one bridge oxygen and two single bonded oxygen. These two double bonds are localized among four oxygens. Below given are resonating structures of \[{{N}_{2}}{{O}_{5}}\]
So, the \[N{{O}_{2}}\]has two resonating structures and \[{{N}_{2}}{{O}_{5}}\] has 3 resonating structures
Note: So, while drawing resonating structures you should be careful about lone pairs and charges. Here all double bonds partially exist. And oxygen has partial negative charge.
Complete step by step solution:
> We know that resonance is the way by which we describe delocalized electrons within certain molecules or polyatomic ions where the bonding can’t be expressed by a single Lewis formula or structure.
> Resonance structures: These are the set of two or more Lewis Structures that collectively describe the electronic bonding of a single polyatomic species including partial bonds and partial charges.
> Resonance structures are capable of describing delocalized electrons that cannot be expressed by a single Lewis formula with an integer number of covalent bonds.
> In case of\[N{{O}_{2}}\],it has one single bonded oxygen and one double bonded oxygen. Or we can say that this double bond delocalized. Below given are resonating structures of \[N{{O}_{2}}\]
> In case of\[{{N}_{2}}{{O}_{5}}\], it has two double bonded oxygens and one bridge oxygen and two single bonded oxygen. These two double bonds are localized among four oxygens. Below given are resonating structures of \[{{N}_{2}}{{O}_{5}}\]
So, the \[N{{O}_{2}}\]has two resonating structures and \[{{N}_{2}}{{O}_{5}}\] has 3 resonating structures
Note: So, while drawing resonating structures you should be careful about lone pairs and charges. Here all double bonds partially exist. And oxygen has partial negative charge.
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