Glucose reacts with bromine water to produce:
A. glyceraldehyde
B. gluconic acid
C. saccharic acid
D. glucaric acid
Answer
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Hint: We know that bromine water is a mild oxidizing agent. It only oxidizes aldehydic group of glucose to carboxylic acid. The other \[ - {\rm{OH}}\] in the chain remains unaffected. It is also known that a glucose molecule contains 6 membered chain with only one aldehydic group.
Complete step by step answer:
We know that glucose has molecular formula \[{{\rm{C}}_{\rm{6}}}{{\rm{H}}_{{\rm{12}}}}{{\rm{O}}_{\rm{6}}}\]. It is a monosaccharide that contains six carbon atoms along with one \[{\rm{CHO}}\] group. So when bromine water which is a mild oxidizing agent is added in glucose, that \[{\rm{CHO}}\] group will get oxidized to \[{\rm{COOH}}\]. The product formed is gluconic acid.
We can write this chemical change as:
So, the correct answer is “Option B”.
Note:
We know that aldehydes are very prone to oxidizing agents. They get easily oxidized to carboxylic acids with any mild oxidizing agent. Also glucose has only one aldehydic group and addition of this oxidizing agent converts this group into \[{\rm{COOH}}\].
Complete step by step answer:
We know that glucose has molecular formula \[{{\rm{C}}_{\rm{6}}}{{\rm{H}}_{{\rm{12}}}}{{\rm{O}}_{\rm{6}}}\]. It is a monosaccharide that contains six carbon atoms along with one \[{\rm{CHO}}\] group. So when bromine water which is a mild oxidizing agent is added in glucose, that \[{\rm{CHO}}\] group will get oxidized to \[{\rm{COOH}}\]. The product formed is gluconic acid.
We can write this chemical change as:
So, the correct answer is “Option B”.
Note:
We know that aldehydes are very prone to oxidizing agents. They get easily oxidized to carboxylic acids with any mild oxidizing agent. Also glucose has only one aldehydic group and addition of this oxidizing agent converts this group into \[{\rm{COOH}}\].
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