Question

How do you graph using the $ x $ and $ y - $ intercept for $ y = 5 $ ?

Answer 1

Hint: We have given an equation of a line as $ y = 5 $ , which is a straight-line equation. A straight-line equation is always linear and represented as $ y = mx + c $ where $ m $ is the slope of the line and $ c $ is the y-intercept and $ \dfrac{{ - c}}{m} $ is the x-intercept

Complete step-by-step answer:
We have equation of line,
  $ y = 5 $
Now we compare this given equation with the general linear equation i.e., $ y = mx + c $
Hence ,
Slope of the given line, $ m = 0 $ .
y-intercept of the given line , $ c = 5 $ .
Therefore, we can say that point $ (0,5) $ lie on the line.
x-intercept of the given line , $ \dfrac{{ - c}}{m} = \dfrac{{ - (5)}}{0} = - \infty $ .
Therefore, we can say that point $ ( - \infty ,0) $ lie on the line.
With the help of two points, we can plot the graph by connecting the points as follow,

Note: Slope of a line can also be found if two points on the line are given . let the two points on the line be $ ({x_1},{y_1}),({x_2},{y_2}) $ respectively.
Then the slope is given by , $ m = \dfrac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}} $ .
Slope is also defined as the ratio of change in $ y $ over the change in $ x $ between any two points.
 y-intercept can also be found by substituting $ x = 0 $ .
Similarly, x-intercept can also be found by substituting $ y = 0 $ .