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Where will the hand of a clock stop if it starts at 2 and makes 12 of a revolution, clockwise?

Answer
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Hint: We will use the property of the clock that the hand of a clock revolves at a complete angle of 360which makes a complete clockwise revolution.

Complete step-by-step solution:
Step 1: To solve this problem, first we will make a clock as shown below:
seo images

In fig (1), the hand of the clock is at 2. Now we know in complete clockwise revolution, the hand of the clock makes an angle of 360. That means the hand of the clock will start from 2 and after making revolution it will again end at 2.
But as per the question, the hand of the clock revolves 12 clockwise.
Step 2: If the hand of the clock making half revolution then the angle form by it will be half of the 360 as shown below:
Angle=3602180
Step 3: Now, by drawing an angle 180, we can find out that the hand of the clock stops at which point as shown in the below diagram:
seo images

So, we can see from figure (2), that the hand of the clock makes an angle of 180 with the point 8.

The hand of the clock will stop at the point 8.

Note: Students should remember that the hand of the clock always revolves in the clockwise direction by making a complete revolution with an angle of 360.
We can also solve this question by the below method:
As we know that there are total 12 symbols in the clock in which the hand of the clock revolves itself.
Now, for making a complete clockwise revolution the hand of the clock will cover all these points and will come back again at the point 2.
But as per the question, it is only making half a revolution so if the hand of the clock is starting from a point 2, then it will cover 6 symbols in the clock which means 2+6=8. So, the answer is 8.
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