Answer
Verified
417.6k+ views
Hint As we know that change in enthalpy of a reaction is the amount of heat released or being absorbed as the reaction takes place. We can calculate the change in enthalpy in different ways depending on the specific situation.
Complete answer:
- We will discuss the simplest way of calculating the enthalpy change which uses the enthalpy of reactants and products. As we know that if we know these quantities then we can use the formula $\Delta H={{H}_{products}}-{{H}_{reactants}}$ to find the overall change.
- If we consider the reaction of sodium ion with chloride ion to form a sodium chloride compound, then we can calculate the enthalpy change in this way.
- As we know that chloride ion has an enthalpy of -167.4 KJ/mol and sodium ion has an enthalpy of -239.7 KJ/mol. And sodium chloride has an enthalpy of about -411 KJ/mol. Now, we will all these values given in the formula of enthalpy change as:
$\begin{align}
& \Delta H=-411KJ/mol-(-239.7KL/mol-167.4KJ/mol) \\
&\implies -411KJ/mol-(-407.1KJ/mol) \\
&\implies -411KJ/mol+407.1KJ/mol) \\
& \implies -3.9KJ/mol \\
\end{align}$
- So, we get the answer that there is almost 4KJ of energy per mole released during the formation of salt.
- Hence, in this way we can calculate the enthalpy change
Note:
- As we know that enthalpy is an energy-like property that has dimensions of energy. It is mainly measured in joules or ergs.
- It is found that there are several factors that affect the enthalpy of reaction, these are the temperature of the system, the concentration of the reactants and the partial pressure of the gases if any are involved.
Complete answer:
- We will discuss the simplest way of calculating the enthalpy change which uses the enthalpy of reactants and products. As we know that if we know these quantities then we can use the formula $\Delta H={{H}_{products}}-{{H}_{reactants}}$ to find the overall change.
- If we consider the reaction of sodium ion with chloride ion to form a sodium chloride compound, then we can calculate the enthalpy change in this way.
- As we know that chloride ion has an enthalpy of -167.4 KJ/mol and sodium ion has an enthalpy of -239.7 KJ/mol. And sodium chloride has an enthalpy of about -411 KJ/mol. Now, we will all these values given in the formula of enthalpy change as:
$\begin{align}
& \Delta H=-411KJ/mol-(-239.7KL/mol-167.4KJ/mol) \\
&\implies -411KJ/mol-(-407.1KJ/mol) \\
&\implies -411KJ/mol+407.1KJ/mol) \\
& \implies -3.9KJ/mol \\
\end{align}$
- So, we get the answer that there is almost 4KJ of energy per mole released during the formation of salt.
- Hence, in this way we can calculate the enthalpy change
Note:
- As we know that enthalpy is an energy-like property that has dimensions of energy. It is mainly measured in joules or ergs.
- It is found that there are several factors that affect the enthalpy of reaction, these are the temperature of the system, the concentration of the reactants and the partial pressure of the gases if any are involved.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
Mark and label the given geoinformation on the outline class 11 social science CBSE
When people say No pun intended what does that mea class 8 english CBSE
Name the states which share their boundary with Indias class 9 social science CBSE
Give an account of the Northern Plains of India class 9 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Trending doubts
Difference Between Plant Cell and Animal Cell
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Which are the Top 10 Largest Countries of the World?
One cusec is equal to how many liters class 8 maths CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
The mountain range which stretches from Gujarat in class 10 social science CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths