
How do you graph ?
Answer
468.3k+ views
Hint: In this question we are supposed to find to draw the graph of a given equation . The given equation is linear in order with respect to both variables and . To plot the graph of this equation we will first find some point i.e., pairs of such that they satisfy the given equation. Then we will place these points on the X-Y plane.
Complete step-by-step solution:
In this question we need to plot the graph of equation . To plot this equation we will first find that this equation is of line, circle or some other 2-D shapes. Since our given equation is of linear order in both the variables, so it can be the equation of a line. Because the equation of a straight line is of the form and our equation is .
We will modify our equation, so that it will be in the form of an equation of line and find the value of its slope and intercept.
Now, we take from L.H.S to R.H.S. So our equation will be in standard form of line.
In our equation we have and . Since the given equation is of a straight line.
Now, we will find some point which lies on the given equation by putting values of and respectively.
Let us take then value of in , we get .
Similarly, Let us take then value of in , we get .
Similarly, Let us take then value of in , we get .
Similarly, Let us take then value of in , we get .
Similarly, Let us take then value of in , we get .Now we have some points which lies on , here is the graph
These blue dots are the above points which we find by assuming the value of .
Note: To check whether your graph is correct or not just take any point from the line put in the given equation, if it satisfies then your plotted graph is correct. For example: is a point on the line. Putting in the equation , we get
Hence the plotted graph of equation is correct.
Complete step-by-step solution:
In this question we need to plot the graph of equation
We will modify our equation, so that it will be in the form of an equation of line and find the value of its slope and intercept.
Now, we take
In our equation we have
Now, we will find some point which lies on the given equation by putting values of
Let us take
Similarly, Let us take
Similarly, Let us take
Similarly, Let us take
Similarly, Let us take

These blue dots are the above points which we find by assuming the value of
Note: To check whether your graph is correct or not just take any point from the line put in the given equation, if it satisfies then your plotted graph is correct. For example:
Hence the plotted graph of equation
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