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How do you graph y2x=8?

Answer
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Hint: In this question we are supposed to find to draw the graph of a given equation y2x=8. The given equation is linear in order with respect to both variables x and y. To plot the graph of this equation we will first find some point i.e., pairs of x,y such that they satisfy the given equation. Then we will place these points on the X-Y plane.

Complete step-by-step solution:
In this question we need to plot the graph of equationy2x=8. To plot this equation we will first find that this equation is of line, circle or some other 2-D shapes. Since our given equation is of linear order in both the variables, so it can be the equation of a line. Because the equation of a straight line is of the form y=mx+c and our equation is y2x=8.
We will modify our equation, so that it will be in the form of an equation of line and find the value of its slope and intercept.
Now, we take 2x from L.H.S to R.H.S. So our equation will be in standard form of line.
y2x=8y=2x+8
In our equation we have m=2 and c=8. Since the given equation y2x=8 is of a straight line.
Now, we will find some point which lies on the given equation by putting values of x and y respectively.
y2x=8y=2x+8 eq(1)
Let us take x=0 then value of x in eq(1), we gety=8.
Similarly, Let us take x=1then value of x in eq(1), we gety=10.
Similarly, Let us take x=2then value of x in eq(1), we gety=12.
Similarly, Let us take x=1then value of x in eq(1), we gety=6.
Similarly, Let us take x=2 then value of x in eq(1), we get y=4.Now we have some points which lies on y2x=8, here is the graph
seo images


These blue dots are the above points which we find by assuming the value of x.
Note: To check whether your graph is correct or not just take any point from the line put in the given equation, if it satisfies then your plotted graph is correct. For example: (6,4) is a point on the line. Putting (6,4) in the equationy2x=8, we get
42(6)=84+12=88=8LHS=RHS
Hence the plotted graph of equationy2x=8 is correct.
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