Answer
Verified
430.2k+ views
Hint:In order to determine the graph of the above equation, square on both sides of the equation, you will get an equation quadratic in variable $y$. So the graph will be a rightward opening parabola defined only for positive y-axis .Having the domain of the equation as $x \in \left[ { - 4,\infty } \right)$. Find out some good values of the equation by putting $x = - 3,0,5$ plot on the cartesian to get the accurate graph .
Complete step by step solution:
We are given a equation that is having two variables i.e.
$y = \sqrt {x + 4} $---(1)
Let’s find out the domain of the above equation, to know on what values of variable $x$the graph is going to be drawn.
We can clearly see that the $x + 4$ cannot be negative. Therefore, equation is defined for all $x + 4
\geqslant 0 \Rightarrow x \geqslant - 4$
$\therefore x \in \left[ { - 4,\infty } \right)$
We cannot directly sketch the graph of the above equation. So we will be square on both sides of the equation. We get,
$
{\left( y \right)^2} = {\left( {\sqrt {x + 4} } \right)^2} \\
{y^2} = x + 4\,\,\, - - - - - (2) \\
$
Graph will be a rightward opening parabola as the equation is quadratic in $y$
Since, from the equation (2) we can clearly see that the value of y is always positive.
So the graph is not defined for the negative y-axis.
Now we are going to graph, For that we are jumping on the cartesian plane.
Let's find out some good values of $x\, and \,y$, in other words some coordinates of points for equation (1).
Hence we’ve successfully plotted our graph of $y = \sqrt {x + 4} $
Additional Information:
1.DOMAIN: Let R be a relation from a set A to a set B. Then the set of all first components or
coordinates of the ordered pairs belonging to R is called the domain of R.
Thus, domain of $R = \left\{ {a:(a,b) \in R} \right\}$
2.RANGE: Let R be a relation from a set A to a set B . Then the set of all second components or coordinates of the ordered pairs belonging to R is called the range of R.
Thus, Range of $R = \left\{ {b:\left( {a,b} \right) \in R} \right\}$
Note:
1. Cartesian Plane: A Cartesian Plane is given its name by the French mathematician Rene Descartes ,who first used this plane in the field of mathematics .It is defined as the two mutually perpendicular number line , the one which is horizontal is given name x-axis and the one which is vertical is known as y-axis. With the help of these axes we can plot any point on this cartesian plane with the help of an ordered pair of numbers.
2.Draw the cartesian plane only with the help of a straight ruler and pencil to get the perfect and accurate results.
Complete step by step solution:
We are given a equation that is having two variables i.e.
$y = \sqrt {x + 4} $---(1)
Let’s find out the domain of the above equation, to know on what values of variable $x$the graph is going to be drawn.
We can clearly see that the $x + 4$ cannot be negative. Therefore, equation is defined for all $x + 4
\geqslant 0 \Rightarrow x \geqslant - 4$
$\therefore x \in \left[ { - 4,\infty } \right)$
We cannot directly sketch the graph of the above equation. So we will be square on both sides of the equation. We get,
$
{\left( y \right)^2} = {\left( {\sqrt {x + 4} } \right)^2} \\
{y^2} = x + 4\,\,\, - - - - - (2) \\
$
Graph will be a rightward opening parabola as the equation is quadratic in $y$
Since, from the equation (2) we can clearly see that the value of y is always positive.
So the graph is not defined for the negative y-axis.
Now we are going to graph, For that we are jumping on the cartesian plane.
Let's find out some good values of $x\, and \,y$, in other words some coordinates of points for equation (1).
Hence we’ve successfully plotted our graph of $y = \sqrt {x + 4} $
Additional Information:
1.DOMAIN: Let R be a relation from a set A to a set B. Then the set of all first components or
coordinates of the ordered pairs belonging to R is called the domain of R.
Thus, domain of $R = \left\{ {a:(a,b) \in R} \right\}$
2.RANGE: Let R be a relation from a set A to a set B . Then the set of all second components or coordinates of the ordered pairs belonging to R is called the range of R.
Thus, Range of $R = \left\{ {b:\left( {a,b} \right) \in R} \right\}$
Note:
1. Cartesian Plane: A Cartesian Plane is given its name by the French mathematician Rene Descartes ,who first used this plane in the field of mathematics .It is defined as the two mutually perpendicular number line , the one which is horizontal is given name x-axis and the one which is vertical is known as y-axis. With the help of these axes we can plot any point on this cartesian plane with the help of an ordered pair of numbers.
2.Draw the cartesian plane only with the help of a straight ruler and pencil to get the perfect and accurate results.
Recently Updated Pages
10 Examples of Evaporation in Daily Life with Explanations
10 Examples of Diffusion in Everyday Life
1 g of dry green algae absorb 47 times 10 3 moles of class 11 chemistry CBSE
If the coordinates of the points A B and C be 443 23 class 10 maths JEE_Main
If the mean of the set of numbers x1x2xn is bar x then class 10 maths JEE_Main
What is the meaning of celestial class 10 social science CBSE
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Which are the Top 10 Largest Countries of the World?
How do you graph the function fx 4x class 9 maths CBSE
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Why is there a time difference of about 5 hours between class 10 social science CBSE
Give 10 examples for herbs , shrubs , climbers , creepers