Answer
398.4k+ views
Hint: First define the given function y by finding its domain, i.e., the values of x for which the function will be defined. To do this, substitute the term inside the square root greater than or equal to 0. Now, to draw the graph, square both sides of the equation and draw the graph of the parabola obtained. Remove the part of the graph below x – axis to get the answer.
Complete step-by-step solution:
Here, we have been provided with the function \[y=\sqrt{x-4}\] and we are asked to draw its graph. But first we need to find the domain of the function.
Now, the domain of a function \[f\left( x \right)\] is the set of values of x for which the function \[f\left( x \right)\] is defined. In the above question, for the function y to be decided we must have the term inside the square root greater than 0. It can be equal to 0 also but not less than 0. So, we must have,
\[\begin{align}
& \Rightarrow x-4\ge 0 \\
& \Rightarrow x\ge 4 \\
\end{align}\]
\[\Rightarrow \] Domain \[\in \left[ 4,\infty \right)\]
Now, on squaring both sides of the given equation, we get,
\[\Rightarrow {{y}^{2}}=x-4\]
Clearly, we can see that the above relation is a parabola. Here, if we will assume \[{{y}^{2}}=f\left( x \right)=x\] then we can say that the above relation can be written as \[{{y}^{2}}=x-4=f\left( x \right)+c\], where c = -4 units. So, the graph of \[{{y}^{2}}=x-4\] will be shifted 4 units to the right in comparison to the graph of \[{{y}^{2}}=x\]. So, the graph of \[{{y}^{2}}=x-4\] can be given as: -
Now, the original equation is \[y=\sqrt{x-4}\] whose graph we need to draw. As we can see that in the R.H.S. we have the positive square root, so the value of y cannot be negative. That means we need to remove that part of the parabola \[{{y}^{2}}=x-4\] in which y is negative, so the part of the graph below the x – axis needs to be removed. Therefore, we have,
Note: One may note that if we will take values of x less than 4 then the function will become a complex function for which we used another type of plane called ‘argand plane’. Complex functions are not drawn on a cartesian plane. Remember that if you know the graph of \[y=f\left( x \right)\] then you can easily draw the graphs of function \[y=f\left( x \right)+c\]. Here, if ‘c’ is positive then the graph is shifted horizontally left and if ‘c’ is negative then we shift the graph horizontally right.
Complete step-by-step solution:
Here, we have been provided with the function \[y=\sqrt{x-4}\] and we are asked to draw its graph. But first we need to find the domain of the function.
Now, the domain of a function \[f\left( x \right)\] is the set of values of x for which the function \[f\left( x \right)\] is defined. In the above question, for the function y to be decided we must have the term inside the square root greater than 0. It can be equal to 0 also but not less than 0. So, we must have,
\[\begin{align}
& \Rightarrow x-4\ge 0 \\
& \Rightarrow x\ge 4 \\
\end{align}\]
\[\Rightarrow \] Domain \[\in \left[ 4,\infty \right)\]
Now, on squaring both sides of the given equation, we get,
\[\Rightarrow {{y}^{2}}=x-4\]
Clearly, we can see that the above relation is a parabola. Here, if we will assume \[{{y}^{2}}=f\left( x \right)=x\] then we can say that the above relation can be written as \[{{y}^{2}}=x-4=f\left( x \right)+c\], where c = -4 units. So, the graph of \[{{y}^{2}}=x-4\] will be shifted 4 units to the right in comparison to the graph of \[{{y}^{2}}=x\]. So, the graph of \[{{y}^{2}}=x-4\] can be given as: -
![seo images](https://www.vedantu.com/question-sets/ef8ff571-0fd4-49e4-98eb-19ec4f5322bf2037228829393826526.png)
Now, the original equation is \[y=\sqrt{x-4}\] whose graph we need to draw. As we can see that in the R.H.S. we have the positive square root, so the value of y cannot be negative. That means we need to remove that part of the parabola \[{{y}^{2}}=x-4\] in which y is negative, so the part of the graph below the x – axis needs to be removed. Therefore, we have,
![seo images](https://www.vedantu.com/question-sets/8cd08e75-6b66-4151-86df-79b3984bb81f5208736263424155659.png)
Note: One may note that if we will take values of x less than 4 then the function will become a complex function for which we used another type of plane called ‘argand plane’. Complex functions are not drawn on a cartesian plane. Remember that if you know the graph of \[y=f\left( x \right)\] then you can easily draw the graphs of function \[y=f\left( x \right)+c\]. Here, if ‘c’ is positive then the graph is shifted horizontally left and if ‘c’ is negative then we shift the graph horizontally right.
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