Answer
397.5k+ views
Hint: The above question is based on the concept of equations having variables on both the sides. The main approach towards solving the problem is to bring the variable on one side i.e., we must add or subtract from both sides one of the quantities that contains the variable.
Complete step by step solution:
In the above given equation, it contains variables on both sides. We first need to isolate the variable on one side and constants to another side.
To simplify it we could use the division property to isolate the variable and solve the equation. Sometimes, after you simplify you may have a variable and a constant term on the same side of the equal sign.
This will involve choosing one side of the equation containing, and the other side of the equation containing the constant side. This will help us with organization. Then, we will use the Addition and Subtraction Properties of Equality, step by step, to isolate the variable terms on one side of the equation.
Now the given equation,
$12x + 3 = 6x + 3$
We shift the variable terms on the left hand side and constant terms on the right hand side.
\[
\Rightarrow 12x - 6x = 3 - 3 \\
\Rightarrow 6x = 0 \\
\Rightarrow x = \dfrac{0}{6} = 0 \\
\]
By applying division property the final value of x we get is 0.
Note: An important thing to note is that since we get the value of x as 0 ,if we need to cross check the answer is true or not we can substitute the value of x in the equation. If both sides are equal after substituting then the value of x is correct.
Complete step by step solution:
In the above given equation, it contains variables on both sides. We first need to isolate the variable on one side and constants to another side.
To simplify it we could use the division property to isolate the variable and solve the equation. Sometimes, after you simplify you may have a variable and a constant term on the same side of the equal sign.
This will involve choosing one side of the equation containing, and the other side of the equation containing the constant side. This will help us with organization. Then, we will use the Addition and Subtraction Properties of Equality, step by step, to isolate the variable terms on one side of the equation.
Now the given equation,
$12x + 3 = 6x + 3$
We shift the variable terms on the left hand side and constant terms on the right hand side.
\[
\Rightarrow 12x - 6x = 3 - 3 \\
\Rightarrow 6x = 0 \\
\Rightarrow x = \dfrac{0}{6} = 0 \\
\]
By applying division property the final value of x we get is 0.
Note: An important thing to note is that since we get the value of x as 0 ,if we need to cross check the answer is true or not we can substitute the value of x in the equation. If both sides are equal after substituting then the value of x is correct.
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