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How do you solve \[15x=-15\]?

Answer
VerifiedVerified
533.1k+ views
Hint: This question is from the topic of algebra. In this question, we will find the value of x. In solving this question, we will first take the term 15 from the right side of the equation to the left side of the equation. After that, we will take the common term that is 15 in the equation. After that, we will remove that 15 from the equation by dividing 15 to the both sides of the equation. From there, after solving, we will find the value of x.

Complete step by step solution:
Let us solve this question.
In this question, we have asked to solve the equation \[15x=-15\]. Or, we can say that we have to find the value of x from the equation which is given in the question.
The equation which we have to solve is
\[15x=-15\]
Now, we will take the term -15 to the left side of the equation. For that, we will add 15 to both sides of the equation.
So, the above equation can also be written as
\[\Rightarrow 15x+15=-15+15\]
\[\Rightarrow 15x+15=0\]
Now, we will take common 15 in the left side of equation, we will get
\[\Rightarrow 15\left( x+1 \right)=0\]
Now, we divide 15 to the both side of equation, we will get
\[\Rightarrow \dfrac{15}{15}\left( x+1 \right)=\dfrac{0}{15}\]
As we know that zero divided by any number is always zero, so we can write the above equation as
\[\Rightarrow \left( x+1 \right)=0\]
\[\Rightarrow x+1=0\]
Now, subtracting 1 to the both side of the equation, we get
\[\Rightarrow x+1-1=0-1\]
\[\Rightarrow x=-1\]
Hence, we have solved the equation \[15x=-15\] and found the value of x as -1.

Note:
We should have a better knowledge in the topic of algebra to solve this type of question easily. We can solve this question by alternate method.
The equation which we have to solve is
\[15x=-15\]
After dividing 15 to the both side of equation, we get
\[\Rightarrow \dfrac{15x}{15}=\dfrac{-15}{15}\]
Now, we know that if we divide 15 by 15, we will get as 1. So, we can write
\[\Rightarrow x=-1\]
Hence, we have got the same answer from this method too.
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