Answer
Verified
431.7k+ views
Hint: In the given problem we need to solve this for ‘x’. We can solve this using the transposition method. The common transposition method is to do the same thing (mathematically) to both sides of the equation, with the aim of bringing like terms together and isolating the variable (or the unknown quantity).
Complete step-by-step solution:
Given, \[5x + 3 = 23\]
We have the unknown term in the left hand side of the equation, so we transpose the remaining terms to the right hand side of the equation. We transpose 3 to the right hand side of the equation by subtracting 3 on the right hand side of the equation.
\[ \Rightarrow 5x = 23 - 3\]
\[ \Rightarrow 5x = 20\]
Here 5 is multiplied to the variable (unknown value) ‘x’. We transpose 5 to the right hand side of the equation by dividing 5 on the right hand side of the equation.
\[ \Rightarrow x = \dfrac{{20}}{5}\]
\[ \Rightarrow x = 4\]
Note: We can check whether the obtained answer is correct or not. We substitute the obtained value in the given problem.
\[
5(4) + 3 = 23 \\
20 + 3 = 23 \\
\Rightarrow 23 = 23 \\
\]
Hence the obtained answer is correct. If we want to transpose the addition number to any side of the equation we subtract it with the same number on both sides of the equation. Similarly if we want to transpose the negative number to any side of the equation we add with the same number on both sides of the equation. Similarly if we have multiplication we use division to transpose. If we have division we use multiplication to transpose. Follow the same procedure for these kinds of problems.
Complete step-by-step solution:
Given, \[5x + 3 = 23\]
We have the unknown term in the left hand side of the equation, so we transpose the remaining terms to the right hand side of the equation. We transpose 3 to the right hand side of the equation by subtracting 3 on the right hand side of the equation.
\[ \Rightarrow 5x = 23 - 3\]
\[ \Rightarrow 5x = 20\]
Here 5 is multiplied to the variable (unknown value) ‘x’. We transpose 5 to the right hand side of the equation by dividing 5 on the right hand side of the equation.
\[ \Rightarrow x = \dfrac{{20}}{5}\]
\[ \Rightarrow x = 4\]
Note: We can check whether the obtained answer is correct or not. We substitute the obtained value in the given problem.
\[
5(4) + 3 = 23 \\
20 + 3 = 23 \\
\Rightarrow 23 = 23 \\
\]
Hence the obtained answer is correct. If we want to transpose the addition number to any side of the equation we subtract it with the same number on both sides of the equation. Similarly if we want to transpose the negative number to any side of the equation we add with the same number on both sides of the equation. Similarly if we have multiplication we use division to transpose. If we have division we use multiplication to transpose. Follow the same procedure for these kinds of problems.
Recently Updated Pages
Fill in the blanks with suitable prepositions Break class 10 english CBSE
Fill in the blanks with suitable articles Tribune is class 10 english CBSE
Rearrange the following words and phrases to form a class 10 english CBSE
Select the opposite of the given word Permit aGive class 10 english CBSE
Fill in the blank with the most appropriate option class 10 english CBSE
Some places have oneline notices Which option is a class 10 english CBSE
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
How do you graph the function fx 4x class 9 maths CBSE
Which are the Top 10 Largest Countries of the World?
What is the definite integral of zero a constant b class 12 maths CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Define the term system surroundings open system closed class 11 chemistry CBSE
Full Form of IASDMIPSIFSIRSPOLICE class 7 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE