
How do you solve $ 5{x^2} + 5x - 1 = 0 $ ?
Answer
552.3k+ views
Hint: This equation is the quadratic equation. The general form of the quadratic equation is $ a{x^2} + bx + c = 0 $ . Where ‘a’ is the coefficient of $ {x^2} $ , ‘b’ is the coefficient of x and ‘c’ is the constant term.
To solve this equation, we will apply the quadratic formula for the quadratic equation.
The quadratic formula is as below:
$ x = \dfrac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}} $ .
Here, $ \sqrt {{b^2} - 4ac} $ is called the discriminant. And it is denoted by $ \Delta $ .
If $ \Delta $ is greater than 0, then we will get two distinct and real roots.
If $ \Delta $ is less than 0, then we will not get real roots. In this case, we will get two complex numbers.
If $ \Delta $ is equal to 0, then we will get two equal real roots.
Complete step by step answer:
Here, the given quadratic equation is
$ \Rightarrow 5{x^2} + 5x - 1 = 0 $
We want to find the roots.
First, let us compare the above expression with $ a{x^2} + bx + c = 0 $ .
Here, we get the value of ‘a’ is 5, the value of ‘b’ is 5, and the value of ‘c’ is -1.
Now, let us find the discriminant $ \Delta $ .
$ \Rightarrow \Delta = {b^2} - 4ac $
Let us substitute the values.
$ \Rightarrow \Delta = {\left( 5 \right)^2} - 4\left( 5 \right)\left( { - 1} \right) $
Simplify it.
$ \Rightarrow \Delta = 25 + 20 $
Subtract the right-hand side.
$ \Rightarrow \Delta = 45 $
Here, $ \Delta $ is greater than 0, then we will get two distinct real roots.
Now,
$ x = \dfrac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}} $
Now, put all the values.
$ \Rightarrow x = \dfrac{{ - \left( 5 \right) \pm \sqrt {45} }}{{2\left( 5 \right)}} $
That is equal to
$ \Rightarrow x = \dfrac{{ - 5 \pm 3\sqrt 5 i}}{{10}} $
Hence, the two factors are $ \dfrac{{ - 5 + 3\sqrt 5 i}}{{10}} $ and $ \dfrac{{ - 5 - 3\sqrt 5 i}}{{10}} $ .
Note: One important thing is, we can always check our work by multiplying out factors back together, and check that we have got back the original answer.
Here is a list of methods to solve quadratic equations:
• Factorization
• Completing the square
• Using graph
• Quadratic formula
To solve this equation, we will apply the quadratic formula for the quadratic equation.
The quadratic formula is as below:
$ x = \dfrac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}} $ .
Here, $ \sqrt {{b^2} - 4ac} $ is called the discriminant. And it is denoted by $ \Delta $ .
If $ \Delta $ is greater than 0, then we will get two distinct and real roots.
If $ \Delta $ is less than 0, then we will not get real roots. In this case, we will get two complex numbers.
If $ \Delta $ is equal to 0, then we will get two equal real roots.
Complete step by step answer:
Here, the given quadratic equation is
$ \Rightarrow 5{x^2} + 5x - 1 = 0 $
We want to find the roots.
First, let us compare the above expression with $ a{x^2} + bx + c = 0 $ .
Here, we get the value of ‘a’ is 5, the value of ‘b’ is 5, and the value of ‘c’ is -1.
Now, let us find the discriminant $ \Delta $ .
$ \Rightarrow \Delta = {b^2} - 4ac $
Let us substitute the values.
$ \Rightarrow \Delta = {\left( 5 \right)^2} - 4\left( 5 \right)\left( { - 1} \right) $
Simplify it.
$ \Rightarrow \Delta = 25 + 20 $
Subtract the right-hand side.
$ \Rightarrow \Delta = 45 $
Here, $ \Delta $ is greater than 0, then we will get two distinct real roots.
Now,
$ x = \dfrac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}} $
Now, put all the values.
$ \Rightarrow x = \dfrac{{ - \left( 5 \right) \pm \sqrt {45} }}{{2\left( 5 \right)}} $
That is equal to
$ \Rightarrow x = \dfrac{{ - 5 \pm 3\sqrt 5 i}}{{10}} $
Hence, the two factors are $ \dfrac{{ - 5 + 3\sqrt 5 i}}{{10}} $ and $ \dfrac{{ - 5 - 3\sqrt 5 i}}{{10}} $ .
Note: One important thing is, we can always check our work by multiplying out factors back together, and check that we have got back the original answer.
Here is a list of methods to solve quadratic equations:
• Factorization
• Completing the square
• Using graph
• Quadratic formula
Recently Updated Pages
Two men on either side of the cliff 90m height observe class 10 maths CBSE

Cutting of the Chinese melon means A The business and class 10 social science CBSE

Show an aquatic food chain using the following organisms class 10 biology CBSE

How is gypsum formed class 10 chemistry CBSE

If the line 3x + 4y 24 0 intersects the xaxis at t-class-10-maths-CBSE

Sugar present in DNA is A Heptose B Hexone C Tetrose class 10 biology CBSE

Trending doubts
Why is there a time difference of about 5 hours between class 10 social science CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

Indias first jute mill was established in 1854 in A class 10 social science CBSE

Indias first jute mill was established in 1854 in A class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

