Answer
398.4k+ views
Hint: In arithmetic, the cosine work (cos) is a capacity that relates the inside point of a triangle to the length of its sides. The cosine work, alongside the sine and digression work are the three essential geometrical capacities.
Complete step by step answer:
Given$ \Rightarrow $cos$38 = \dfrac{{45}}{x}$
Cos$38 = 0.788010753$
$\eqalign{
& \Rightarrow \dfrac{{\cos }}{1} = \dfrac{{45}}{x} \cr
& \Rightarrow \cos 38x = 45 \cr
& \Rightarrow 0.788010753 \times x = 45 \cr
& \Rightarrow x = \dfrac{{45}}{{0.788010753}} \cr
& \therefore x = 57.10581972 \cr} $
Note: Check the answer by substituting $x = 57.10581972$ in question.
$\eqalign{
& \Rightarrow \operatorname{Cos} 38 = \dfrac{{45}}{x} \cr
& \Rightarrow \cos 38 = \dfrac{{45}}{{57.10581972}} \cr
& \Rightarrow 0.788010753 \cr} $
And cos$38 = 0.788010753$
Complete step by step answer:
Given$ \Rightarrow $cos$38 = \dfrac{{45}}{x}$
Cos$38 = 0.788010753$
$\eqalign{
& \Rightarrow \dfrac{{\cos }}{1} = \dfrac{{45}}{x} \cr
& \Rightarrow \cos 38x = 45 \cr
& \Rightarrow 0.788010753 \times x = 45 \cr
& \Rightarrow x = \dfrac{{45}}{{0.788010753}} \cr
& \therefore x = 57.10581972 \cr} $
Note: Check the answer by substituting $x = 57.10581972$ in question.
$\eqalign{
& \Rightarrow \operatorname{Cos} 38 = \dfrac{{45}}{x} \cr
& \Rightarrow \cos 38 = \dfrac{{45}}{{57.10581972}} \cr
& \Rightarrow 0.788010753 \cr} $
And cos$38 = 0.788010753$
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