Answer
Verified
420k+ views
Hint: Find the common ratio(r) in progression and substitute in sum of n terms formula
First, since we are given the sum to infinity, we have the formula of it, from which we can derive the value of the common ratio which is . Then after finding this, we have to find the sum of the first\[\;n\] term by substituting it and then we get the sum of first \[\;n\] terms.
Complete step by step solution:
We are given that
A series in geometric progression, where
$S$is the sum to infinity of a G.P.
First term is “a”.
Now, we have to find the sum of the first\[\;n\] terms are,
For that we have to find a common ratio. Since we are given the sum of infinite terms
So,
$
S = \dfrac{a}{{1 - r}} \\
1 - r = \dfrac{a}{S} \\
r = 1 - \dfrac{a}{S} \\
$ $
S = \dfrac{a}{{1 - r}} \\
1 - r = \dfrac{a}{S} \\
r = 1 - \dfrac{a}{S} \\
$
Now, we have found the common ratio of the geometric progression.
We can find the required sum now.
The formula.
${S_n} = \dfrac{{a\left( {1 - {r^n}} \right)}}{{1 - r}}$
Now, we substitute the value and get the value.
\[
= \dfrac{{a\left[ {1 - {{\left( {1 - \dfrac{a}{S}} \right)}^n}} \right]}}{{1 - \left( {1 - \dfrac{a}{S}} \right)}} \\
= \dfrac{{a\left[ {1 - {{\left( {1 - \dfrac{a}{S}} \right)}^n}} \right]}}{{\dfrac{a}{S}}} \\
\\
\]
Cancel a in numerator and denominator.
Then, we get
${S_n} = S\left[ {1 - {{\left( {1 - \dfrac{a}{S}} \right)}^n}} \right]$
Which is option(B).
Hence, we have found the sum of the first\[\;n\] terms for the given series in geometric progression.
Therefore, we can say that option ‘B’ is the correct option.
Note: We have to be careful while identifying and substituting in the formula, and identify the formula of sum of infinite terms and finite terms and analyse what is given in the question, so that we can easily substitute in the formula.
First, since we are given the sum to infinity, we have the formula of it, from which we can derive the value of the common ratio which is . Then after finding this, we have to find the sum of the first\[\;n\] term by substituting it and then we get the sum of first \[\;n\] terms.
Complete step by step solution:
We are given that
A series in geometric progression, where
$S$is the sum to infinity of a G.P.
First term is “a”.
Now, we have to find the sum of the first\[\;n\] terms are,
For that we have to find a common ratio. Since we are given the sum of infinite terms
So,
$
S = \dfrac{a}{{1 - r}} \\
1 - r = \dfrac{a}{S} \\
r = 1 - \dfrac{a}{S} \\
$ $
S = \dfrac{a}{{1 - r}} \\
1 - r = \dfrac{a}{S} \\
r = 1 - \dfrac{a}{S} \\
$
Now, we have found the common ratio of the geometric progression.
We can find the required sum now.
The formula.
${S_n} = \dfrac{{a\left( {1 - {r^n}} \right)}}{{1 - r}}$
Now, we substitute the value and get the value.
\[
= \dfrac{{a\left[ {1 - {{\left( {1 - \dfrac{a}{S}} \right)}^n}} \right]}}{{1 - \left( {1 - \dfrac{a}{S}} \right)}} \\
= \dfrac{{a\left[ {1 - {{\left( {1 - \dfrac{a}{S}} \right)}^n}} \right]}}{{\dfrac{a}{S}}} \\
\\
\]
Cancel a in numerator and denominator.
Then, we get
${S_n} = S\left[ {1 - {{\left( {1 - \dfrac{a}{S}} \right)}^n}} \right]$
Which is option(B).
Hence, we have found the sum of the first\[\;n\] terms for the given series in geometric progression.
Therefore, we can say that option ‘B’ is the correct option.
Note: We have to be careful while identifying and substituting in the formula, and identify the formula of sum of infinite terms and finite terms and analyse what is given in the question, so that we can easily substitute in the formula.
Recently Updated Pages
Fill in the blanks with suitable prepositions Break class 10 english CBSE
Fill in the blanks with suitable articles Tribune is class 10 english CBSE
Rearrange the following words and phrases to form a class 10 english CBSE
Select the opposite of the given word Permit aGive class 10 english CBSE
Fill in the blank with the most appropriate option class 10 english CBSE
Some places have oneline notices Which option is a class 10 english CBSE
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
How do you graph the function fx 4x class 9 maths CBSE
When was Karauli Praja Mandal established 11934 21936 class 10 social science CBSE
Which are the Top 10 Largest Countries of the World?
What is the definite integral of zero a constant b class 12 maths CBSE
Why is steel more elastic than rubber class 11 physics CBSE
Distinguish between the following Ferrous and nonferrous class 9 social science CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE