Answer
Verified
394.5k+ views
Hint: The given question involves the arithmetic operations like addition/ subtraction/ multiplication/ division. We need to know the basic formula with the involvement of HCF and LCM to make an easy calculation. Also, we need to know how to separate a variable from constants to solve these types of questions.
Complete step by step solution:
In this question we have,
HCF of \[35 \] and \[45 \] is \[5 \]
And
LCM of \[35 \] and \[45 \] is \[63 \times a \] .
So, it can also be written as,
\[HCF\left( {35,45} \right) = 5 \to \left( 1 \right) \]
\[LCM\left( {35,45} \right) = 63 \times a \to \left( 2 \right) \]
We know that
If \[m,n \] are two positive numbers then,
\[HCF\left( {m,n} \right) \times LCM\left( {m,n} \right) = m \times n \to \left( 3 \right) \]
By comparing the equation \[\left( 1 \right)\& \left( 2 \right) \] with the equation \[\left( 3 \right) \] , we get
\[
HCF\left( {m,n} \right) = HCF\left( {35,45} \right) \\
LCM\left( {m,n} \right) = LCM\left( {35,45} \right) \\
\]
So, we get
\[
m = 35 \\
n = 45 \\
\]
So, the equation \[\left( 3 \right) \] becomes,
\[\left( 3 \right) \to HCF\left( {m,n} \right) \times LCM\left( {m,n} \right) = m \times n \]
\[HCF\left( {35,45} \right) \times LCM\left( {35,45} \right) = 35 \times 45 \]
So, we get
\[HCF\left( {35,45} \right) \times LCM\left( {35,45} \right) = 1575 \to \left( 4 \right) \]
Let’s substitute the equation \[\left( 1 \right)\& \left( 2 \right) \] in the equation \[\left( 4 \right) \] , we get
\[\left( 4 \right) \to HCF\left( {35,45} \right) \times LCM\left( {35,45} \right) = 1575 \]
\[5 \times 63 \times a = 1575 \]
Let’s separate the term \[a \] from the above equation we get,
\[a = \dfrac{{1575}}{{5 \times 63}} = \dfrac{{1575}}{{315}} \]
By using calculator we get,
\[a = \dfrac{{1575}}{{315}} = 5 \]
So, the final answer is,
\[a = 5 \]
Note: This question describes the arithmetic operations like addition/ subtraction/ multiplication/ division. We would create an equation from the given data to solve these types of questions. Also, we would separate the unknown term from the known terms to solve the given problem. Also, note that when we move one term from the left-hand side to the right-hand side of the equation the arithmetic functions can be modified as follows,
The addition operation can be converted into the subtraction process.
The subtraction process can be converted into the addition process.
The multiplication process can be converted into the division process.
The division process can be converted into a multiplication process
Complete step by step solution:
In this question we have,
HCF of \[35 \] and \[45 \] is \[5 \]
And
LCM of \[35 \] and \[45 \] is \[63 \times a \] .
So, it can also be written as,
\[HCF\left( {35,45} \right) = 5 \to \left( 1 \right) \]
\[LCM\left( {35,45} \right) = 63 \times a \to \left( 2 \right) \]
We know that
If \[m,n \] are two positive numbers then,
\[HCF\left( {m,n} \right) \times LCM\left( {m,n} \right) = m \times n \to \left( 3 \right) \]
By comparing the equation \[\left( 1 \right)\& \left( 2 \right) \] with the equation \[\left( 3 \right) \] , we get
\[
HCF\left( {m,n} \right) = HCF\left( {35,45} \right) \\
LCM\left( {m,n} \right) = LCM\left( {35,45} \right) \\
\]
So, we get
\[
m = 35 \\
n = 45 \\
\]
So, the equation \[\left( 3 \right) \] becomes,
\[\left( 3 \right) \to HCF\left( {m,n} \right) \times LCM\left( {m,n} \right) = m \times n \]
\[HCF\left( {35,45} \right) \times LCM\left( {35,45} \right) = 35 \times 45 \]
So, we get
\[HCF\left( {35,45} \right) \times LCM\left( {35,45} \right) = 1575 \to \left( 4 \right) \]
Let’s substitute the equation \[\left( 1 \right)\& \left( 2 \right) \] in the equation \[\left( 4 \right) \] , we get
\[\left( 4 \right) \to HCF\left( {35,45} \right) \times LCM\left( {35,45} \right) = 1575 \]
\[5 \times 63 \times a = 1575 \]
Let’s separate the term \[a \] from the above equation we get,
\[a = \dfrac{{1575}}{{5 \times 63}} = \dfrac{{1575}}{{315}} \]
By using calculator we get,
\[a = \dfrac{{1575}}{{315}} = 5 \]
So, the final answer is,
\[a = 5 \]
Note: This question describes the arithmetic operations like addition/ subtraction/ multiplication/ division. We would create an equation from the given data to solve these types of questions. Also, we would separate the unknown term from the known terms to solve the given problem. Also, note that when we move one term from the left-hand side to the right-hand side of the equation the arithmetic functions can be modified as follows,
The addition operation can be converted into the subtraction process.
The subtraction process can be converted into the addition process.
The multiplication process can be converted into the division process.
The division process can be converted into a multiplication process
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
Mark and label the given geoinformation on the outline class 11 social science CBSE
When people say No pun intended what does that mea class 8 english CBSE
Name the states which share their boundary with Indias class 9 social science CBSE
Give an account of the Northern Plains of India class 9 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Trending doubts
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Difference Between Plant Cell and Animal Cell
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Which are the Top 10 Largest Countries of the World?
Give 10 examples for herbs , shrubs , climbers , creepers
10 examples of evaporation in daily life with explanations
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Why is there a time difference of about 5 hours between class 10 social science CBSE