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In 2007 - 08, the number of students appeared for class X examination was 1,05,332 and in 200809 the number was 1,16,054. If 88,151 students pass the examination in 200708 and 103804 students in 200809. What is the increase or decrease in pass % in class X result?

Answer
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Hint: In this question, we have the number of students appeared and passed in specific years. We need to first calculate the number of students who passed in the examination. Then we will get the passing percentage of class X for both the years. Then we can easily find out the required solution.

Complete step by step answer:
It is given that, in 200708, the number of students appeared for class X examination was 1,05,332 and in 200809, the number was 1,16,054.
Also given that, 88,151 students pass the examination in 200708 and 103804 students in 200809.
We need to find out the increase or decrease in pass % in class X result.
The number of students appearing for class X examination in 200708 was 1,05,332.
The number of students passing the examination in 200708=88,151.
The percentage of the students, who passed the examination =88151105332×100=83.68%
The number of students appearing for class X examination in 200809 was 1,16,054.
The number of students passing the examination in 200809=103804.
The percentage of the students, who passed the examination =103804116054×100=89.44%
Since the passing percentage in 200809 is more than the passing percentage in 200708, it has increased.
The increase in pass % in class X result is =(89.4483.68)%=5.76%

The increase in pass % in class X result is 5.76%

Note:
Here we use the given in the question, the values are large so we have to concentrate on calculations of this problem.
In mathematics, a percentage is a number or ratio that represents a fraction of 100. It is often denoted by the symbol "%"
The percentage of x is denoted by x% and defined by, x%=x100

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