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In a titrant experiment, 10 ml of FeCl2 solution consumed 25ml of standard K2Cr2O7 solution to reach the equivalence point. This standard K2Cr2O7 solution is prepared by dissolving 1.225g of K2Cr2O7 in 250ml water. The concentration of the FeCl2 solution is closest to:
[Given: molecular weight of K2Cr2O7 = 204g mol1]
A.0.25N
B.0.50N
C.0.10N
D.0.04N

Answer
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Hint: We need to remember that when two chemicals react with each other the formation of the product is going to depend on the energy required to convert chemical reactants into products. If the energy to convert reactants into products is just too high, then the reaction isn’t going to happen.

Complete step by step answer:
As we know that the ferric chloride may be a common compound of iron and chlorine during which iron possesses +3 oxidation state. From the question we’ve,
Given: V = 250 ml, V1 = 10 ml, V2 = 25 ml, N1 =? m1 = 1.225g and M = 294g/ mol
We know that N=M×nf
When FeCl2 reacts with K2Cr2O7 its Fe2+ ion gets converted into Fe3+ ion.
From the above equation,
  No. of equivalent of FeCl2 = no. of equivalent of K2Cr2O7
Therefore, N1V1=N2V2
Substituting the values of V1 and Missing superscript or subscript argument2 we get,
N1×10=M×nf×25
  N1×10=nV(L)×nf×25
On substituting the known values we get,
 N1×10=1.225/294250×103×6×25
On simplification we get,
N1=0,25N
FeCl2+K2Cr2O7Fe+3+Cr+3

Note:
-We have to remember that the IUPAC name of ferric chloride is Iron (III) chloride or iron trichloride. Apart from ferric chloride it’s several common names like molysite and Flores martis. It possesses various colours like as in its anhydrous form it appears black-green or purple while in its hydrous form it appears yellow solid.
-The formation of the products in a chemical reaction is going to depend on ionization energy of the chemicals. If the reaction needs the highest amount of ionization energy we’ve to use a catalyst to complete the reaction.