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In benzene, the triple bond consists of-
(A)- one sp-sp sigma bond and two p-p pi bonds
(B)- two sp-sp sigma bonds and one p-p pi bonds
(C)- one $s{{p}^{2}}-s{{p}^{2}}$ sigma bond and one p-p pi bond
(D)- one $s{{p}^{2}}-s{{p}^{2}}$ sigma bond, one$s{{p}^{2}}-s{{p}^{2}}$ pi bond and one p-p pi bond.

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Answer
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Hint: A triple bond in benzene is actually a benzene molecule. All three bonds are different in nature, two of them being coplanar and one out of the plane. The two bonds are the same as that of a normal benzene ring and the third one lies perpendicular to the p-orbitals of the aromatic pi system.

Complete step by step solution:
The structure of benzene and benzyne (benzene with a triple bond) are-
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$s{{p}^{2}}$ Orbitals involved in the triple bond are at ${{90}^{\circ }}$ to the p- orbitals of the aromatic pi system involved. Additional pi bonds cannot overlap the aromatic pi system, hence they are not coplanar.
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There is already a sigma $s{{p}^{2}}-s{{p}^{2}}$ bond between two carbon atoms. And a regular p-p pi bond as that present in a normal benzene ring.

So the correct answer is option (D)- one $s{{p}^{2}}-s{{p}^{2}}$ sigma bond, one$s{{p}^{2}}-s{{p}^{2}}$ pi bond and one p-p pi bond.

Additional information:
The triple bond in a six-membered ring makes benzyne a highly reactive molecule as poor overlap leads to a very weak triple bond, easily attacked by a nucleophile.

Note: One should note that the benzene bond is not like the triple bond of acetylene which is a very strong bond as the $s{{p}^{2}}$ orbitals are not parallel and therefore involve poor overlap in benzyne.