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Hint:We can predict the number of bond pair-lone pair repulsions at${90^ \circ }$ by drawing its structure. The shape of $ICl_4^ - $ is square planar because it has four bond pairs and lone pairs. The geometry is octahedral.
Complete step-by-step answer:Before solving the question we have to look at the structure to determine their number of bond pair-lone pairs.
Now, the structure of $ICl_4^ - $ is,
Iodine $\left( I \right)$ has $7$ electron it its valence shell in $ICl_4^ - $eight electron participate in formation of compound
Shape of $ICl_4^ - $is square planar. Since its geometry is octahedral, lone pairs reside above and below the square planar. In $ICl_4^ - $each lone pair interacts with the $4$ bond pair.
So, Number of bond pair-lone pair repulsion=Total number of lone pairs multiplied by number of bond pairs by which they interact. We have two lone pairs and four bond pairs
Number of bond pairs-lone pairs repulsion$ = 2 \times 4$
$ = 8$
Thus, there is $8$ bond pairs-lone pairs repulsion at ${90^ \circ }$ . So, the correct option is $B.$
Note: Valence Shell Electron Pair Repulsion Theory $\left( {VSEPR} \right)$ .This is a very useful theory to predict the geometry or shape of a number of polyatomic molecules or ions on a non-transition element. This theory says that shapes of a species depend on the number of and nature of electron pairs surrounding the central atom of a species.
Table summarizes the relationship between the number of electron pairs that are bond pairs and lone pairs and the shape or geometry.
Complete step-by-step answer:Before solving the question we have to look at the structure to determine their number of bond pair-lone pairs.
Now, the structure of $ICl_4^ - $ is,
Iodine $\left( I \right)$ has $7$ electron it its valence shell in $ICl_4^ - $eight electron participate in formation of compound
Shape of $ICl_4^ - $is square planar. Since its geometry is octahedral, lone pairs reside above and below the square planar. In $ICl_4^ - $each lone pair interacts with the $4$ bond pair.
So, Number of bond pair-lone pair repulsion=Total number of lone pairs multiplied by number of bond pairs by which they interact. We have two lone pairs and four bond pairs
Number of bond pairs-lone pairs repulsion$ = 2 \times 4$
$ = 8$
Thus, there is $8$ bond pairs-lone pairs repulsion at ${90^ \circ }$ . So, the correct option is $B.$
Note: Valence Shell Electron Pair Repulsion Theory $\left( {VSEPR} \right)$ .This is a very useful theory to predict the geometry or shape of a number of polyatomic molecules or ions on a non-transition element. This theory says that shapes of a species depend on the number of and nature of electron pairs surrounding the central atom of a species.
Table summarizes the relationship between the number of electron pairs that are bond pairs and lone pairs and the shape or geometry.
Total number of electron pairs | Shape |
2 | Linear |
3 | Trigonal planar |
4 | Tetrahedral |
5 | Trigonal bipyramidal |
6 | Octahedral |
7 | Pentagonal bipyramidal |
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