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In SI unit, the gravitational unit of force is called
(A). $Gf$
(B). $Kgf$
(C). $N$
(D). All

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Answer
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Hint: The gravitational unit force is defined as the force experienced by a body of unit mass, that is $1kg$, by the gravitation due to Earth. Use the mentioned definition to derive the SI unit of gravitational unit force.

Complete step by step answer:
There are various types of force in this universe like Normal force, Frictional force, Tension force, Air resistance force, Spring force, Gravitational force, etc. Every force in the universe will be represented by the same dimensional formula which is \[\left[ {{M}^{1}}{{L}^{1}}{{T}^{-2}} \right]\].
The SI unit system defines $1N$ of force as the absolute unit of force necessary to provide a mass of $1kg$ with an acceleration of $1m/{{s}^{2}}$.
Whereas the gravitational unit force is defined as the force experienced by a body of unit mass, that is $1kg$, by the gravitation due to Earth. The unit of this force is $Kgf$. Let us calculate the value $1Kgf$ holds in $N$. From the definition, we understand that we are required to calculate the force on a unit mass object on the surface of the Earth.
We know,
\[\begin{align}
  & \Rightarrow \text{Force}=\text{mass}\times \text{acceleration} \\
 & \Rightarrow \text{F=m}\times \text{g} \\
 & \Rightarrow F=1\times 9.8kgm/{{s}^{2}} \\
 & \Rightarrow F=9.8N \\
\end{align}\]
This means one unit of $Kgf$ is equivalent to $9.8N$ Force.
Therefore, the answer to this question is B. $Kgf$.
Additional Information:
The acceleration due to gravity $g$around the surface of the Earth is approximately $9.8m/{{s}^{2}}$. The value of gravity changes as the height from Earth at which it is observed is increased. As the height is increased, gravity decreases. Similarly, gravity inside the Earth decreases with decreasing depth.

Note: Much like how Horse Power and Joules are units of energy, $Kgf$ and Newton are units of force. Please take care that the question asks the SI unit of unit gravitational force and not simply force, which would be Newton.