Question

In the competition, $95{\text{ kg}}$food is sufficient for $5$ persons. Find the quantity of food required for $23$ persons.

Answer 1

Hint: If $5$ persons can eat $95{\text{ kg}}$ food, then $1$ person can eat $\dfrac{{95}}{5}{\text{kg}}$ food.
Now if you find the quantity consumed by one person, then you can easily find the quantity of food required for $23$ persons.

Complete step by step solution:
So, in this question it is given that in the competition there are some people and among them $95{\text{kg}}$ food is sufficient for $5$ persons. Now we need to find the quantity of food for $23$ persons instead of \[5\] people.
So as we are given that for $5$ persons $95{\text{kg}}$ food is sufficient. So for finding the quantity of food required for $23$ persons, we need to first find the quantity of food for one person.
$5$ persons consumes $95{\text{ kg}}$ food
$1$ person consumes $\dfrac{{95}}{5}{\text{kg}}$ food
So as we come to know that
$1$ person consumes $\dfrac{{95}}{5}{\text{kg}}$ food
Which means that one person consumes $19{\text{kg}}$ of food. So we need to find the quantity of food required for $23$ persons.
So when we come to know that one person consumes $19{\text{kg}}$ of food, then the quantity of food consumed by n people will be $19n{\text{ kg}}$
So we need to find for \[23\] people so here we get that $n = 23$
So the total amount of food required by $23$ people will be $19 \times 23 = 437{\text{kg}}$

So at least $437{\text{kg}}$ is required for $23$ people for the condition given that $5$ people consume $95{\text{kg}}$ of food.

Note: If we are given that m people require n quantity of food, then for one person $\dfrac{n}{m}$ quantity is required.
Now for p number of people, $\dfrac{{pn}}{m}$ quantity of food is required. Here p, n, m can be any number.