
In the ground state of$C{u^ + }$, the number of shells occupied, sub-shells occupied, filled orbitals and unpaired electrons respectively are:
[Atomic no. of copper=$29$]
A. 4,8,15,0
B. 3,6,15,1
C. 3,6,14,0
D. 4,7,14,2
Answer
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Hint:
Calculate the atomic number and fill the orbital with the principal quantum number as shell and subshell division as per the electronic configuration rule.
Complete answer:
In an atom, orbits are the energy level in which the electrons move and their path on which they move around the nucleus is called orbitals. Shells is the collection of subshells sharing the same principal quantum number denoted by (n) and are represented as K,L.M,N giving the shell a particular number. Sub-Shells are the various orbits in which a certain defined maximum number of electrons can be filled denoted by s,p,d,f. Principal quantum number, angular momentum quantum number and magnetic quantum number are represented by orbital energy.
The atomic number of $Cu$ is 29.the electronic configuration of copper the first two electrons will go in $1{s^2}$ and then another two electrons will go in $2{s^2}$. The next six electrons will enter in $2{p^6}$ and then another two electrons will go in $3{s^2}$and then another six electrons will go in $3{P^6}$ and then two will enter in $4{s^2}$and remaining six electrons will enter in $3{d^{10}}$ . but in the case of $C{u^ + }$ one electron is loosed from the $4{s^1}$ making this sub shell half filled and giving the electronic configuration as
$C{u^ + } = 1{s^2},2{s^2},2{p^6},3{s^2},3{p^6},3{d^{10}}$
Shells used in this orbitals are $s,p,d$ i.e n=3
The subshell occupied are 6.
The amount of total filled orbitals are calculated with principal quantum number, ${n^2}$ . for each energy level the n=1 and then it will go on:
Filled orbitals = $1 + 1 + 3 + 1 + 3 + 5)$
= 14
The unpaired electron in $C{u^ + }$ is zero.
The filled orbital for $C{u^ + }$is 3,6,14,0
Hence the correct option is Option (C).
Note:
Shell/subshell of an atom represents the relativistic particles confined by the law of quantum where they behave as wave particles surrounded by a nucleus.
Calculate the atomic number and fill the orbital with the principal quantum number as shell and subshell division as per the electronic configuration rule.
Complete answer:
In an atom, orbits are the energy level in which the electrons move and their path on which they move around the nucleus is called orbitals. Shells is the collection of subshells sharing the same principal quantum number denoted by (n) and are represented as K,L.M,N giving the shell a particular number. Sub-Shells are the various orbits in which a certain defined maximum number of electrons can be filled denoted by s,p,d,f. Principal quantum number, angular momentum quantum number and magnetic quantum number are represented by orbital energy.
The atomic number of $Cu$ is 29.the electronic configuration of copper the first two electrons will go in $1{s^2}$ and then another two electrons will go in $2{s^2}$. The next six electrons will enter in $2{p^6}$ and then another two electrons will go in $3{s^2}$and then another six electrons will go in $3{P^6}$ and then two will enter in $4{s^2}$and remaining six electrons will enter in $3{d^{10}}$ . but in the case of $C{u^ + }$ one electron is loosed from the $4{s^1}$ making this sub shell half filled and giving the electronic configuration as
$C{u^ + } = 1{s^2},2{s^2},2{p^6},3{s^2},3{p^6},3{d^{10}}$
Shells used in this orbitals are $s,p,d$ i.e n=3
The subshell occupied are 6.
The amount of total filled orbitals are calculated with principal quantum number, ${n^2}$ . for each energy level the n=1 and then it will go on:
Filled orbitals = $1 + 1 + 3 + 1 + 3 + 5)$
= 14
The unpaired electron in $C{u^ + }$ is zero.
The filled orbital for $C{u^ + }$is 3,6,14,0
Hence the correct option is Option (C).
Note:
Shell/subshell of an atom represents the relativistic particles confined by the law of quantum where they behave as wave particles surrounded by a nucleus.
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