Question

Inorganic graphite is:
(A). $${\left(BN\right)}_n$$
(B) $B{F}_4$
(C) $B_2{H}_6$
(D) $B_2{N}_2{H}_6$

Answer 1

Hint: Inorganic graphite is an inorganic compound whose structure is like graphite with alternating atoms replacing the carbon atoms in hexagonal structure.

Complete step by step answer:
Boron nitride is sometimes referred to as ‘inorganic graphite’ because its structure is like graphite with alternating boron and nitrogen atoms replacing the carbon atoms in the hexagonal structure.
$BN$ is isoelectronic to a similarly structured carbon lattice and thus exists in various crystalline forms.
The structure of $BN$ is

Figure-The structure of Boron Nitride

Additional information:
Boron nitride is produced synthetically. Hexagonal boron nitride is obtained by the reacting trioxide $\left(B_2{O}_3\right)$ or boric acid $\left(H_{3}B{O}_3\right)$ with ammonia ${\left(NH\right)}_3$ or $\left(N{H}_{2}CON{H}_2\right)$ in a nitrogen atmosphere.
$B_2{O}_3+2N{H}_3\to 2BN+3H_{2}O$ $\left(T={900}^{\circ }c\right)$
$B{\left(OH\right)}_3+N{H}_3\to BN+3H_{2}O$ $\left(T={900}^{\circ }c\right)$
$B_2{O}_3+CO{\left(N{H}_2\right)}_2\to 2BN+C{O}_2+2H_{2}O$ $\left(T>{1000}^{\circ }c\right)$
$B_2{O}_3+3Ca{B}_6+IO{N}_2\to 2OBN+3CaO$ $\left(T>{1500}^{\circ }c\right)$
Similar to graphite, various molecules such as $N{H}_3$ or alkali metals can be intercalated into hexagonal boron nitride, that is inserted between its layers. Both experiment and theory suggest the intercalation is much more difficult for $BN$ than for graphite.

Note:
$BN$ is the most widely used polymorph. It is a good lubricant at both low and high temperature. $BN$ is used as an lubricant when electrical conductivity or chemical reactivity of graphite would be problematic.