Question

IUPAC name of $H_2\left[PtC{L}_6\right]$ is:
A. Hydrogen hexachloroplatinate (IV)
B. Dihydrogen hexachloroplatinate (IV)
C. Hydrogen hexachloroplatinic (IV) acid
D. Hexachloroplatinic (IV) acid

Answer 1

Hint- In order to deal with this question first we have to understand the compound structure and its functional groups, then according to its structure and functional groups we will determine its IUPAC name. In order to name any compound there are some set of rules defined by IUPAC which are used here.

Complete answer:
Given compound is $H_2\left[PtC{L}_6\right]$
The compound contains six chlorine ligands and platinum metal in +4 oxidation state. The oxidation state is written in roman numerals inside parenthesis.
When cation is present outside the brackets then the suffix "ate" is added to the name of metal present inside the brackets.
Since there are two hydrogen atoms so the name would be dihydrogen for molecules.
And due to the presence of 6 chlorine and platinum the name would be hexachloroplatinate
Hence, the IUPAC name of $H_2\left[PtC{L}_6\right]$ is Dihydrogen hexachloroplatinate (IV).

So, the correct answer is option B.

Note- In order to name any compound students must remember some basic set of rules of IUPAC nomenclature which are commonly used. In summary, the name of the compound is written out with the substituent in alphabetical order followed by the base name (derived from the number of carbons in the parent chain). Commas are used between numbers and dashes are used between letters and numbers.