Answer
Verified
459.3k+ views
Hint: In order to solve this problem we need to know that area of rhombus $\dfrac{1}{2}{d_1} \times {d_2}$. We need to find the radius of the circle and then we need to apply the formula of the area of the rhombus after finding the length of its diagonals. Doing this will solve your problem and will give you the right answer.
Complete step-by-step answer:
The diagram for this problem can be drawn as:
As it is given to us that ${C_1}$ and ${C_2}$ are the centres of the given circles and also that P and Q are the points of intersection of these circles and hence we can say that,
${C_1}$=$\left( {\dfrac{2}{2},\dfrac{2}{2}} \right) = \left( {1,1} \right)$
Similarly,
${C_2}$=$\left( {\dfrac{6}{2},\dfrac{6}{2}} \right) = \left( {3,3} \right)$
Now our Radius ${r_1} = \sqrt {{1^2} + {1^2} + 2} = \sqrt 4 = 2$
Similarly Radius ${r_2} = 2$ and hence
We can say that the quadrilateral is Rhombus since all side are equal.
We see that P${C_1}$, P${C_2}$, Q${C_1}$, Q${C_2}$ are radii of two circles
And hence, P${C_1}$=${r_1}$ =2
And diagonals bisect at O= $\left( {\dfrac{{1 + 3}}{2},\dfrac{{1 + 3}}{2}} \right)$ =(2,2)
Now since diagonals are perpendicular in Rhombus and hence
$ \Rightarrow P{C_1}^2 = P{O^2} + O{C_1}^2$
And hence on putting the value, we have
$
\Rightarrow P{O^2} = {\left( 2 \right)^2} - {\left( {\sqrt 2 } \right)^2} \\
\Rightarrow PO = \sqrt 2 \\
$
$ \Rightarrow PQ = {d_1} = 2\sqrt 2 ,\;\;{C_1}{C_2} = {d_2} = 2\sqrt 2 $
Now Area of Rhombus=$\dfrac{1}{2}{d_1} \times {d_2}$
And hence on putting the value, we have
Area of Rhombus= $\dfrac{1}{2} \times 2\sqrt 2 \times 2\sqrt 2 $
And hence on doing the multiplication, we have
Area of Rhombus=4 square unit
Note: In this type of question first of all we have to find the value of radius and with the help of that we can identify the geometry of the figure and then we have to find the measurement of the diagonal and finally with the help of that we can Area of the required geometry. Knowing this and proceeding like this you will get the right answer.
Complete step-by-step answer:
The diagram for this problem can be drawn as:
As it is given to us that ${C_1}$ and ${C_2}$ are the centres of the given circles and also that P and Q are the points of intersection of these circles and hence we can say that,
${C_1}$=$\left( {\dfrac{2}{2},\dfrac{2}{2}} \right) = \left( {1,1} \right)$
Similarly,
${C_2}$=$\left( {\dfrac{6}{2},\dfrac{6}{2}} \right) = \left( {3,3} \right)$
Now our Radius ${r_1} = \sqrt {{1^2} + {1^2} + 2} = \sqrt 4 = 2$
Similarly Radius ${r_2} = 2$ and hence
We can say that the quadrilateral is Rhombus since all side are equal.
We see that P${C_1}$, P${C_2}$, Q${C_1}$, Q${C_2}$ are radii of two circles
And hence, P${C_1}$=${r_1}$ =2
And diagonals bisect at O= $\left( {\dfrac{{1 + 3}}{2},\dfrac{{1 + 3}}{2}} \right)$ =(2,2)
Now since diagonals are perpendicular in Rhombus and hence
$ \Rightarrow P{C_1}^2 = P{O^2} + O{C_1}^2$
And hence on putting the value, we have
$
\Rightarrow P{O^2} = {\left( 2 \right)^2} - {\left( {\sqrt 2 } \right)^2} \\
\Rightarrow PO = \sqrt 2 \\
$
$ \Rightarrow PQ = {d_1} = 2\sqrt 2 ,\;\;{C_1}{C_2} = {d_2} = 2\sqrt 2 $
Now Area of Rhombus=$\dfrac{1}{2}{d_1} \times {d_2}$
And hence on putting the value, we have
Area of Rhombus= $\dfrac{1}{2} \times 2\sqrt 2 \times 2\sqrt 2 $
And hence on doing the multiplication, we have
Area of Rhombus=4 square unit
Note: In this type of question first of all we have to find the value of radius and with the help of that we can identify the geometry of the figure and then we have to find the measurement of the diagonal and finally with the help of that we can Area of the required geometry. Knowing this and proceeding like this you will get the right answer.
Recently Updated Pages
10 Examples of Evaporation in Daily Life with Explanations
10 Examples of Diffusion in Everyday Life
1 g of dry green algae absorb 47 times 10 3 moles of class 11 chemistry CBSE
If x be real then the maximum value of 5 + 4x 4x2 will class 10 maths JEE_Main
If the coordinates of the points A B and C be 443 23 class 10 maths JEE_Main
What happens when dilute hydrochloric acid is added class 10 chemistry JEE_Main
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Which are the Top 10 Largest Countries of the World?
How do you graph the function fx 4x class 9 maths CBSE
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
In the tincture of iodine which is solute and solv class 11 chemistry CBSE
Why is there a time difference of about 5 hours between class 10 social science CBSE