
What mass of $C{O_2}$ will be formed when 6g of carbon is burnt in 32g of oxygen?
A. 38g
B. 12g
C. 26g
D. 22g
Answer
601.2k+ views
Hint: First, we will mention the above reaction and the basic amounts of carbon and oxygen used in it. Then we will mention the amount given in the question and find out the amount of $C{O_2}$ given by 1gm of Carbon and then the amount given by 6gm of Carbon. Refer to the solution below to understand better.
Complete step-by-step answer:
Colourless gas with a soft, strong scent and a bitter taste, Carbon Dioxide ($C{O_2}$). This is one of the most important global warming greenhouse gases, but it is a small component in the Earth's environment (approximately 3 volumes per 10,000), created through burning of carbon-containing fuels, through fermentation and by breathing of animals and used by plants in carbohydrate photosynthesis.
The above-mentioned reaction of $C{O_2}$ can be written as-
$ \Rightarrow C + {O_2} \to C{O_2}$
The atomic mass of C is $12g/mol$
The atomic mass of ${O_2}$ is $32g/mol$
And the atomic mass of $C{O_2}$ is $44g/mol$
It is given in the question that the reaction is carried with 6gm/mol rather than 12gm/mol.
Since we know that in the basic reaction $C + {O_2} \to C{O_2}$-
12gm of C gives 44gm of $C{O_2}$
Thus, 1gm of C will give $\dfrac{{44}}{{12}}gm$ of $C{O_2}$.
Hence, 6gm of C will give-
$
\Rightarrow \dfrac{{44}}{{12}} \times 6 \\
\\
\Rightarrow 22gm \\
$
Thus, 22gm of $C{O_2}$ will be given by 6gm of C.
Hence, option D is the correct option.
Note: The existence of $C{O_2}$ gas in the atmosphere prohibits the transfer to space of any of the radiant energy obtained from Earth resulting in a 'greenhouse effect.' It has been developed to regain as the by-product of hydrogen synthesization preparation for ammonia, lime kiln, and other products for various specific applications from flue gases.
Complete step-by-step answer:
Colourless gas with a soft, strong scent and a bitter taste, Carbon Dioxide ($C{O_2}$). This is one of the most important global warming greenhouse gases, but it is a small component in the Earth's environment (approximately 3 volumes per 10,000), created through burning of carbon-containing fuels, through fermentation and by breathing of animals and used by plants in carbohydrate photosynthesis.
The above-mentioned reaction of $C{O_2}$ can be written as-
$ \Rightarrow C + {O_2} \to C{O_2}$
The atomic mass of C is $12g/mol$
The atomic mass of ${O_2}$ is $32g/mol$
And the atomic mass of $C{O_2}$ is $44g/mol$
It is given in the question that the reaction is carried with 6gm/mol rather than 12gm/mol.
Since we know that in the basic reaction $C + {O_2} \to C{O_2}$-
12gm of C gives 44gm of $C{O_2}$
Thus, 1gm of C will give $\dfrac{{44}}{{12}}gm$ of $C{O_2}$.
Hence, 6gm of C will give-
$
\Rightarrow \dfrac{{44}}{{12}} \times 6 \\
\\
\Rightarrow 22gm \\
$
Thus, 22gm of $C{O_2}$ will be given by 6gm of C.
Hence, option D is the correct option.
Note: The existence of $C{O_2}$ gas in the atmosphere prohibits the transfer to space of any of the radiant energy obtained from Earth resulting in a 'greenhouse effect.' It has been developed to regain as the by-product of hydrogen synthesization preparation for ammonia, lime kiln, and other products for various specific applications from flue gases.
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