Answer
Verified
423k+ views
Hint: Aspartame is an artificial sweetener which is a non-saccharide sweetener. This is having \[200\] times sweeter than sucrose. The aspartame is substituted over sugar in foods and beverages. Aspartame is a methyl ester of the phenylalanine dipeptide of aspartic acid. In the place of sugar, the aspartame can be used for reducing the calories. Aspartame is having the formula of \[{C_{14}}{H_{18}}{N_2}{O_5}\,\] .
Complete step by step solution:
The \[1\,g\] of molecules will be equal to \[1\] mole.
In equation;
\[1\,g\]of molecule \[ = \,\,1\,\]mole
Since, \[1\] mole contains Avogadro’s number (\[{N_A}\] ) of molecule
So, \[1\,mole\, = \,6.022\, \times \,{10^{23}}\,molecule\]
Therefore, for \[1\] molecule will be;
\[1\,\,molecule\, = \,\dfrac{1}{{6.022\, \times \,{{10}^{23}}}}\,g\,\,molecule\]
So, the answer will be;
\[1\,molecule\, = 1.66\, \times \,{10^{ - 24}}\,g\,molecule\]
\[1\] mole Aspartame contains Avogadro’s number (\[{N_A}\] ) of molecule.
Number of moles is calculated by using below given formula;
\[n\,\, = \,\,\dfrac{{mass}}{{molar\,mass}}\]
where \[n\] is the amount in moles \[(mol)\] , mass in grams \[\;(g)\] , and molar mass in grams per mole \[\;(g/mol)\] .
The given values are;
Mass of aspartame= \[5{\text{ }}mg\]
Molar mass of aspartame; \[{C_{14}}{H_{18}}{N_2}{O_5}\,\] ;
There are \[14\] Carbon atoms and carbon molar mass is \[\left( {12.0{\text{ }}g/mol} \right)\] ,
\[18\] Hydrogens atoms and hydrogen’s molar mass is \[\left( {1.008{\text{ }}g/mol} \right)\]
\[2\] Nitrogen atoms and nitrogen’s molar mass is \[\left( {{\text{14}}{\text{.0 }}g/mol} \right)\]
and \[5\] Oxygen atom and the oxygen’s molar mass is \[\left( {16.0{\text{ }}g/mol} \right){\text{ }}\]
Molar mass of \[{C_{14}}{H_{18}}{N_2}{O_5}\,\] ;
\[\left( {14 \times 12.0{\text{ }}g/mol{\text{ }}C} \right){\text{ }} + {\text{ }}\left( {18 \times 1.00{\text{ }}g/mol{\text{ }}H} \right){\text{ }} + {\text{ }}\left( {2 \times 14.0{\text{ }}g/mol{\text{ N}}} \right){\text{ }} + {\text{ }}\left( {5 \times 16.0{\text{ }}g/mol{\text{ }}O} \right){\text{ }}\] \[ = {\text{ 214 }}g/mol{\text{ }}{C_{14}}{H_{18}}{N_2}{O_5}\,\]
\[n\,\, = \,\,\dfrac{{5\,mg}}{{214\,g/mol}}\]
Since,
\[1\,g = \,{10^3}\,mg\]
Therefore,
\[ = \,\dfrac{{5\, \times \,{{10}^3}\,g}}{{214\,g/mol}}\]
\[ = 1.70\, \times \,{10^{ - 5}}\,mol\]
So, the number of moles \[ = 1.70\, \times \,{10^{ - 5}}\,mol\]
Using the Avogadro’s constant, we need to convert the values into molecules;
\[1.70 \times {10^{ - 5}}\,\,mol\, \times \,\dfrac{{6.022\, \times \,{{10}^{23}}\,\,molecules}}{{1\,mol}}\,\]
\[ = \,\,1\, \times \,{10^{19}}\,\,molecules\] of aspartame.
Note: A mole is a unit measurement for the amount of substance in an international system of units i.e., SI unit. A mole of a particle or a mole of a substance is defined as \[6.02214076 \times {10^{23}}\] of a chemical unit, that can be ions, atoms, molecules, etc. Originally it was defined as the number of atoms in \[12{\text{ }}g\] of carbon-12.
Complete step by step solution:
The \[1\,g\] of molecules will be equal to \[1\] mole.
In equation;
\[1\,g\]of molecule \[ = \,\,1\,\]mole
Since, \[1\] mole contains Avogadro’s number (\[{N_A}\] ) of molecule
So, \[1\,mole\, = \,6.022\, \times \,{10^{23}}\,molecule\]
Therefore, for \[1\] molecule will be;
\[1\,\,molecule\, = \,\dfrac{1}{{6.022\, \times \,{{10}^{23}}}}\,g\,\,molecule\]
So, the answer will be;
\[1\,molecule\, = 1.66\, \times \,{10^{ - 24}}\,g\,molecule\]
\[1\] mole Aspartame contains Avogadro’s number (\[{N_A}\] ) of molecule.
Number of moles is calculated by using below given formula;
\[n\,\, = \,\,\dfrac{{mass}}{{molar\,mass}}\]
where \[n\] is the amount in moles \[(mol)\] , mass in grams \[\;(g)\] , and molar mass in grams per mole \[\;(g/mol)\] .
The given values are;
Mass of aspartame= \[5{\text{ }}mg\]
Molar mass of aspartame; \[{C_{14}}{H_{18}}{N_2}{O_5}\,\] ;
There are \[14\] Carbon atoms and carbon molar mass is \[\left( {12.0{\text{ }}g/mol} \right)\] ,
\[18\] Hydrogens atoms and hydrogen’s molar mass is \[\left( {1.008{\text{ }}g/mol} \right)\]
\[2\] Nitrogen atoms and nitrogen’s molar mass is \[\left( {{\text{14}}{\text{.0 }}g/mol} \right)\]
and \[5\] Oxygen atom and the oxygen’s molar mass is \[\left( {16.0{\text{ }}g/mol} \right){\text{ }}\]
Molar mass of \[{C_{14}}{H_{18}}{N_2}{O_5}\,\] ;
\[\left( {14 \times 12.0{\text{ }}g/mol{\text{ }}C} \right){\text{ }} + {\text{ }}\left( {18 \times 1.00{\text{ }}g/mol{\text{ }}H} \right){\text{ }} + {\text{ }}\left( {2 \times 14.0{\text{ }}g/mol{\text{ N}}} \right){\text{ }} + {\text{ }}\left( {5 \times 16.0{\text{ }}g/mol{\text{ }}O} \right){\text{ }}\] \[ = {\text{ 214 }}g/mol{\text{ }}{C_{14}}{H_{18}}{N_2}{O_5}\,\]
\[n\,\, = \,\,\dfrac{{5\,mg}}{{214\,g/mol}}\]
Since,
\[1\,g = \,{10^3}\,mg\]
Therefore,
\[ = \,\dfrac{{5\, \times \,{{10}^3}\,g}}{{214\,g/mol}}\]
\[ = 1.70\, \times \,{10^{ - 5}}\,mol\]
So, the number of moles \[ = 1.70\, \times \,{10^{ - 5}}\,mol\]
Using the Avogadro’s constant, we need to convert the values into molecules;
\[1.70 \times {10^{ - 5}}\,\,mol\, \times \,\dfrac{{6.022\, \times \,{{10}^{23}}\,\,molecules}}{{1\,mol}}\,\]
\[ = \,\,1\, \times \,{10^{19}}\,\,molecules\] of aspartame.
Note: A mole is a unit measurement for the amount of substance in an international system of units i.e., SI unit. A mole of a particle or a mole of a substance is defined as \[6.02214076 \times {10^{23}}\] of a chemical unit, that can be ions, atoms, molecules, etc. Originally it was defined as the number of atoms in \[12{\text{ }}g\] of carbon-12.
Recently Updated Pages
Who among the following was the religious guru of class 7 social science CBSE
what is the correct chronological order of the following class 10 social science CBSE
Which of the following was not the actual cause for class 10 social science CBSE
Which of the following statements is not correct A class 10 social science CBSE
Which of the following leaders was not present in the class 10 social science CBSE
Garampani Sanctuary is located at A Diphu Assam B Gangtok class 10 social science CBSE
Trending doubts
A rainbow has circular shape because A The earth is class 11 physics CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Which are the Top 10 Largest Countries of the World?
How do you graph the function fx 4x class 9 maths CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Give 10 examples for herbs , shrubs , climbers , creepers
Change the following sentences into negative and interrogative class 10 english CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Why is there a time difference of about 5 hours between class 10 social science CBSE