Question

What is the most common oxidation state of fluorine?

Answer 1

Hint: As we know that the oxidation state of an atom can be described as the hypothetical charge which would be held by that atom if all of its bonds with atoms are completely ionic in nature. So here we have to tell the most common oxidation state of fluorine.

Complete answer:
Let us first understand the concept of oxidation state and know about fluorine as well as its most common oxidation state as follows:-
-Oxidation state: It can be described as the hypothetical charge which would be held by that atom if all of its bonds with atoms are completely ionic in nature or in simple words we can say that it is the total number of electrons which an atom either gains or losses in order to form a chemical bond with another atom.
-Fluorine: It is a chemical element denoted by symbol ‘F’ and has atomic number 9. It belongs to group-17 that is a halogen group and is the lightest halogen. It exists as a highly toxic, pale yellow diatomic gas at standard conditions. Being the most electronegative element, it is extremely reactive because it reacts with all other elements (except for argon, neon, and helium).
-As it belongs to the halogen group, so it has 7 electrons in its valence shell and only requires 1 electron to complete its octet, therefore its most common oxidation state is -1.
-Hence the most common oxidation state of fluorine is -1.

Note:
-Remember that the concept of oxidation state is very useful in various reactions as well as it helps us to tell the shape of molecules and compounds, therefore you must study and learn how to calculate and use it in different types of questions.