Now use numbers $1 - 6$ to make your own magic triangle.
Rule: Numbers on each side must add up to $10$
Answer
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Hint: Here we have to solve the question by a trick that we have to place odd numbers on the corner points and even numbers on the mid-points of each side. And the succeeding number of the corner point is the midpoint of the opposite side.
Complete step-by-step answer:
Here in the sides $AB$, $BC$ and $CA$ we have three boxes so if you look in first box that is in point $A$ we have written $1$ so it’s opposite point is located on the side $BC$ which is the midpoint and we have written $2$ in the box as the succeeding number of $1$ is $2$.
Similarly the same concept applies in all the cases it is just a trick there is no hard and fast rule behind it.
Now let us calculate the length of each side of the box
Therefore in case of side AB we get-$6 + 3 + 1 = 10$
In case of side $BC$ we get- $3 + 2 + 5 = 10$
In case of side CA we get $5 + 4 + 1 = 10$
Note: A triangle is a close ended two dimensional figure which has three sides and the sum of all the angles is $180_{}^0$.
Note: It is to be noted that there is no hard and fast rule to solve the question and it is a technique by which it can be solved but there may be other techniques also which you may apply to solve the question. You just have to keep in mind that you need to make ten in all the sides.
Complete step-by-step answer:
Here in the sides $AB$, $BC$ and $CA$ we have three boxes so if you look in first box that is in point $A$ we have written $1$ so it’s opposite point is located on the side $BC$ which is the midpoint and we have written $2$ in the box as the succeeding number of $1$ is $2$.
Similarly the same concept applies in all the cases it is just a trick there is no hard and fast rule behind it.
Now let us calculate the length of each side of the box
Therefore in case of side AB we get-$6 + 3 + 1 = 10$
In case of side $BC$ we get- $3 + 2 + 5 = 10$
In case of side CA we get $5 + 4 + 1 = 10$
Note: A triangle is a close ended two dimensional figure which has three sides and the sum of all the angles is $180_{}^0$.
Note: It is to be noted that there is no hard and fast rule to solve the question and it is a technique by which it can be solved but there may be other techniques also which you may apply to solve the question. You just have to keep in mind that you need to make ten in all the sides.
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