
Number of atoms in 560 grams of \[\text{Fe}\]is:
A.Twice that of 70 g ${{\text{N}}_{\text{2}}}$
B.Half that of 20 g ${{\text{H}}_{\text{2}}}$
C.Both A and B
D.None of the above.
Answer
563.1k+ views
Hint:This problem is based on the concept of “mole”, which is a unit of measurement and is equal to $6.023\times {{10}^{23}}$particles of any substance, where the word “particles” refer to atoms, molecules, ions, and other subatomic particles.
Complete step by step answer:
The atomic weight of iron = 56 grams
One gram atomic weight of iron is equal to one mole of iron atoms.
Therefore, 56 grams of iron =$6.023\times {{10}^{23}}$ atoms of iron.
Hence, 560 grams of iron =$6.023\times {{10}^{24}}$ atoms of iron = 10 times the Avogadro’s number of atoms.
Now, the molecular weight of nitrogen = 28 grams,
Therefore, 28 grams of nitrogen =$6.023\times {{10}^{23}}$ molecules of nitrogen =$2\times 6.023\times {{10}^{23}}$ atoms of nitrogen, as each molecule of nitrogen has 2 atoms.
Therefore 70 gram of nitrogen =$2\times 6.023\times {{10}^{23}}\times \dfrac{70}{28}$ atoms of nitrogen = $5\times 6.023\times {{10}^{23}}$ atoms of nitrogen = 5 times the Avogadro’s number.
Therefore the number of atoms in 560 grams of iron is twice that in 70 grams of nitrogen.
Molecular weight of hydrogen = 2 grams, therefore 2 grams of hydrogen = $6.023\times {{10}^{23}}$ molecules of hydrogen =$2\times 6.023\times {{10}^{23}}$ atoms of hydrogen, as each molecule of hydrogen has 2 atoms.
Therefore 20 grams of hydrogen = $2\times 6.023\times {{10}^{23}}\times \dfrac{20}{2}$ atoms of nitrogen = $20\times 6.023\times {{10}^{23}}$ atoms of nitrogen = 20 times the Avogadro’s number.
Therefore the number of atoms in 560 grams of iron is half that in 70 grams of nitrogen.
Hence, both A and B are correct answers.
So, option C is correct.
Note:
The gram molecular weight of a compound is equal to the sum of the atomic weights of all the atoms present in the molecule, expressed in grams, while the gram atomic weight can be defined as the weight of the atoms expressed in grams. The atomic weight of an element will be twice its molecular weight when it forms homo-atomic compounds.
Complete step by step answer:
The atomic weight of iron = 56 grams
One gram atomic weight of iron is equal to one mole of iron atoms.
Therefore, 56 grams of iron =$6.023\times {{10}^{23}}$ atoms of iron.
Hence, 560 grams of iron =$6.023\times {{10}^{24}}$ atoms of iron = 10 times the Avogadro’s number of atoms.
Now, the molecular weight of nitrogen = 28 grams,
Therefore, 28 grams of nitrogen =$6.023\times {{10}^{23}}$ molecules of nitrogen =$2\times 6.023\times {{10}^{23}}$ atoms of nitrogen, as each molecule of nitrogen has 2 atoms.
Therefore 70 gram of nitrogen =$2\times 6.023\times {{10}^{23}}\times \dfrac{70}{28}$ atoms of nitrogen = $5\times 6.023\times {{10}^{23}}$ atoms of nitrogen = 5 times the Avogadro’s number.
Therefore the number of atoms in 560 grams of iron is twice that in 70 grams of nitrogen.
Molecular weight of hydrogen = 2 grams, therefore 2 grams of hydrogen = $6.023\times {{10}^{23}}$ molecules of hydrogen =$2\times 6.023\times {{10}^{23}}$ atoms of hydrogen, as each molecule of hydrogen has 2 atoms.
Therefore 20 grams of hydrogen = $2\times 6.023\times {{10}^{23}}\times \dfrac{20}{2}$ atoms of nitrogen = $20\times 6.023\times {{10}^{23}}$ atoms of nitrogen = 20 times the Avogadro’s number.
Therefore the number of atoms in 560 grams of iron is half that in 70 grams of nitrogen.
Hence, both A and B are correct answers.
So, option C is correct.
Note:
The gram molecular weight of a compound is equal to the sum of the atomic weights of all the atoms present in the molecule, expressed in grams, while the gram atomic weight can be defined as the weight of the atoms expressed in grams. The atomic weight of an element will be twice its molecular weight when it forms homo-atomic compounds.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Explain zero factorial class 11 maths CBSE

What organs are located on the left side of your body class 11 biology CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

How do I convert ms to kmh Give an example class 11 physics CBSE

