Number of positive integers x for which $ f\left( x \right) = {x^3} - 8{x^2} + 20x - 13 $ , is a prime number is:
(A) $ 1 $
(B) $ 2 $
(C) $ 3 $
(D) $ 4 $
Answer
Verified
400.2k+ views
Hint: In the given question, we are given a function in the variable x and we have to find the number of positive integers x for which the function assumes a prime number value. So, we first factorize the given function into its factors. We use the factor theorem to find the factors of the cubic polynomial function. Then, we analyze the product of the prime factors in order to make the value of the function a prime number. A thorough understanding of functions, division algorithms and its applications will be of great significance.
Complete step-by-step answer:
In the given problem, we are required to find the number of positive integers for which the function $ f\left( x \right) = {x^3} - 8{x^2} + 20x - 13 $ assumes a prime number value.
So, we first find the factors of the polynomial function $ f\left( x \right) = {x^3} - 8{x^2} + 20x - 13 $ using the factor theorem.
According to the factor theorem, if the value of the variable obtained on equating the divisor to zero is a root of the polynomial, then the divisor polynomial is a factor of the dividend polynomial.
Now, let us substitute the value of the variable x as $ 1 $ in the function $ f\left( x \right) = {x^3} - 8{x^2} + 20x - 13 $ .
So, we get,
$ \Rightarrow f\left( 1 \right) = {1^3} - 8{\left( 1 \right)^2} + 20\left( 1 \right) - 13 $
Simplifying the expression further, we get,
$ \Rightarrow f\left( 1 \right) = 1 - 8 + 20 - 13 $
$ \Rightarrow f\left( 1 \right) = 0 $
Since the value of polynomial function $ f\left( x \right) = {x^3} - 8{x^2} + 20x - 13 $ for $ x = 1 $ is zero, then according to the factor theorem, $ \left( {x - 1} \right) $ is a factor of the polynomial function $ f\left( x \right) = {x^3} - 8{x^2} + 20x - 13 $ .
Now, factoring the polynomial function to factor out $ \left( {x - 1} \right) $ , we get,
$ \Rightarrow f\left( x \right) = {x^3} - {x^2} - 7{x^2} + 7x + 13x - 13 $
$ \Rightarrow f\left( x \right) = {x^2}\left( {x - 1} \right) - 7x\left( {x - 1} \right) + 13\left( {x - 1} \right) $
Taking $ \left( {x - 1} \right) $ common from al the terms, we get,
$ \Rightarrow f\left( x \right) = \left( {{x^2} - 7x + 13} \right)\left( {x - 1} \right) $
Now, for the function $ f\left( x \right) = {x^3} - 8{x^2} + 20x - 13 $ to be a prime number, one of the factors of the function must be $ 1 $ and the other factor must be a prime number.
So, there are two cases.
Case $ 1 $ : When $ \left( {x - 1} \right) = 1 $ and $ \left( {{x^2} - 7x + 13} \right) $ is a prime factor.
So, $ \left( {x - 1} \right) = 1 $
$ \Rightarrow x = 2 $
Hence, the value of x comes out to be $ 2 $ .
Now, we find the value of $ \left( {{x^2} - 7x + 13} \right) $ for $ x = 2 $ .
$ \Rightarrow {2^2} - 7\left( 2 \right) + 13 $
$ \Rightarrow 4 - 14 + 13 = 3 $
Therefore, $ x = 2 $ is a positive integral value of x for which the function $ f\left( x \right) = {x^3} - 8{x^2} + 20x - 13 $ is a prime number.
Case $ 2 $ : When $ \left( {{x^2} - 7x + 13} \right) = 1 $ and $ \left( {x - 1} \right) $ is a prime factor.
So, $ \left( {{x^2} - 7x + 13} \right) = 1 $
$ \Rightarrow {x^2} - 7x + 12 = 0 $
Solving the quadratic equation using splitting the middle term method, we get,
$ \Rightarrow {x^2} - 3x - 4x + 12 = 0 $
$ \Rightarrow x\left( {x - 3} \right) - 4\left( {x - 3} \right) = 0 $
Taking $ \left( {x - 3} \right) $ common from the terms, we get,
$ \Rightarrow \left( {x - 4} \right)\left( {x - 3} \right) = 0 $
So, $ x = 3 $ or $ x = 4 $
Now, we find the value of $ \left( {x - 1} \right) $ for $ x = 3 $ and $ x = 4 $ .
So, $ \left( {x - 1} \right) = 2 $ for $ x = 3 $ .
Also, $ \left( {x - 1} \right) = 3 $ for $ x = 4 $ .
Therefore, $ x = 3 $ and $ x = 4 $ are the positive integral values of x for which the function $ f\left( x \right) = {x^3} - 8{x^2} + 20x - 13 $ is a prime number.
Hence, the total number of positive integers for which $ f\left( x \right) = {x^3} - 8{x^2} + 20x - 13 $ is a prime number is $ 3 $ .
Therefore, option (C) is correct.
So, the correct answer is “Option C”.
Note: One must know the significance of the factor theorem in order to solve such problems. Substitution of a variable involves putting a certain value in place of the variable. That specified value may be a certain number or even any other variable. We must take care of the calculations while doing such problems. We must know the basics of the number system to solve such problems. Prime numbers are basic building blocks of arithmetic.
Complete step-by-step answer:
In the given problem, we are required to find the number of positive integers for which the function $ f\left( x \right) = {x^3} - 8{x^2} + 20x - 13 $ assumes a prime number value.
So, we first find the factors of the polynomial function $ f\left( x \right) = {x^3} - 8{x^2} + 20x - 13 $ using the factor theorem.
According to the factor theorem, if the value of the variable obtained on equating the divisor to zero is a root of the polynomial, then the divisor polynomial is a factor of the dividend polynomial.
Now, let us substitute the value of the variable x as $ 1 $ in the function $ f\left( x \right) = {x^3} - 8{x^2} + 20x - 13 $ .
So, we get,
$ \Rightarrow f\left( 1 \right) = {1^3} - 8{\left( 1 \right)^2} + 20\left( 1 \right) - 13 $
Simplifying the expression further, we get,
$ \Rightarrow f\left( 1 \right) = 1 - 8 + 20 - 13 $
$ \Rightarrow f\left( 1 \right) = 0 $
Since the value of polynomial function $ f\left( x \right) = {x^3} - 8{x^2} + 20x - 13 $ for $ x = 1 $ is zero, then according to the factor theorem, $ \left( {x - 1} \right) $ is a factor of the polynomial function $ f\left( x \right) = {x^3} - 8{x^2} + 20x - 13 $ .
Now, factoring the polynomial function to factor out $ \left( {x - 1} \right) $ , we get,
$ \Rightarrow f\left( x \right) = {x^3} - {x^2} - 7{x^2} + 7x + 13x - 13 $
$ \Rightarrow f\left( x \right) = {x^2}\left( {x - 1} \right) - 7x\left( {x - 1} \right) + 13\left( {x - 1} \right) $
Taking $ \left( {x - 1} \right) $ common from al the terms, we get,
$ \Rightarrow f\left( x \right) = \left( {{x^2} - 7x + 13} \right)\left( {x - 1} \right) $
Now, for the function $ f\left( x \right) = {x^3} - 8{x^2} + 20x - 13 $ to be a prime number, one of the factors of the function must be $ 1 $ and the other factor must be a prime number.
So, there are two cases.
Case $ 1 $ : When $ \left( {x - 1} \right) = 1 $ and $ \left( {{x^2} - 7x + 13} \right) $ is a prime factor.
So, $ \left( {x - 1} \right) = 1 $
$ \Rightarrow x = 2 $
Hence, the value of x comes out to be $ 2 $ .
Now, we find the value of $ \left( {{x^2} - 7x + 13} \right) $ for $ x = 2 $ .
$ \Rightarrow {2^2} - 7\left( 2 \right) + 13 $
$ \Rightarrow 4 - 14 + 13 = 3 $
Therefore, $ x = 2 $ is a positive integral value of x for which the function $ f\left( x \right) = {x^3} - 8{x^2} + 20x - 13 $ is a prime number.
Case $ 2 $ : When $ \left( {{x^2} - 7x + 13} \right) = 1 $ and $ \left( {x - 1} \right) $ is a prime factor.
So, $ \left( {{x^2} - 7x + 13} \right) = 1 $
$ \Rightarrow {x^2} - 7x + 12 = 0 $
Solving the quadratic equation using splitting the middle term method, we get,
$ \Rightarrow {x^2} - 3x - 4x + 12 = 0 $
$ \Rightarrow x\left( {x - 3} \right) - 4\left( {x - 3} \right) = 0 $
Taking $ \left( {x - 3} \right) $ common from the terms, we get,
$ \Rightarrow \left( {x - 4} \right)\left( {x - 3} \right) = 0 $
So, $ x = 3 $ or $ x = 4 $
Now, we find the value of $ \left( {x - 1} \right) $ for $ x = 3 $ and $ x = 4 $ .
So, $ \left( {x - 1} \right) = 2 $ for $ x = 3 $ .
Also, $ \left( {x - 1} \right) = 3 $ for $ x = 4 $ .
Therefore, $ x = 3 $ and $ x = 4 $ are the positive integral values of x for which the function $ f\left( x \right) = {x^3} - 8{x^2} + 20x - 13 $ is a prime number.
Hence, the total number of positive integers for which $ f\left( x \right) = {x^3} - 8{x^2} + 20x - 13 $ is a prime number is $ 3 $ .
Therefore, option (C) is correct.
So, the correct answer is “Option C”.
Note: One must know the significance of the factor theorem in order to solve such problems. Substitution of a variable involves putting a certain value in place of the variable. That specified value may be a certain number or even any other variable. We must take care of the calculations while doing such problems. We must know the basics of the number system to solve such problems. Prime numbers are basic building blocks of arithmetic.
Recently Updated Pages
Master Class 10 General Knowledge: Engaging Questions & Answers for Success
Master Class 10 Computer Science: Engaging Questions & Answers for Success
Master Class 10 Science: Engaging Questions & Answers for Success
Master Class 10 Social Science: Engaging Questions & Answers for Success
Master Class 10 Maths: Engaging Questions & Answers for Success
Master Class 10 English: Engaging Questions & Answers for Success
Trending doubts
When people say No pun intended what does that mea class 8 english CBSE
Which king started the organization of the Kumbh fair class 8 social science CBSE
What is BLO What is the full form of BLO class 8 social science CBSE
Advantages and disadvantages of science
Write a letter to the Municipal Commissioner to inform class 8 english CBSE
Summary of the poem Where the Mind is Without Fear class 8 english CBSE